Can someone please help me with this problem 30 points!!!!
1 answer:
You have to make a proportion:
We know that there are 360 degrees (whole) in a circle and the shaded region is 106 degrees (part)
The other proportion will be x over 100, since the whole of percent is always 100 and we are looking for the part.
Look at the image below for the proportion
You get
10600 = 360x
Divide 360 to both sides to isolate x
10600/360 = 360x/360
x= 29.4444
So...
29%
Hope this helped!
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Check the picture below
now, we know is a parallelogram, so the diagonals will bisect
looking at the picture, the interior angles are not right-angles, and thus is not a rectangle, and is not a square either, due to the same reason
is it a rhombus? well, a rhombus, is a parallelogram, that's "slanted" per se, but regardless of how slanted it may be, the sides are all equal
now, we don't need to check the length of both pairs, just one of the segments of each pair, let's check only then JK and KL, the ones in red in the picture, since each pair of segments are twin, if JK = KL, then that means all sides are equal
![\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) J&({{-7 }}\quad ,&{{ -2}})\quad % (c,d) K&({{ 0}}\quad ,&{{ 4}})\\\\ K&({{ 0}}\quad ,&{{ 4}})\quad % (c,d) L&({{ 9}}\quad ,&{{ 2}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ JK=\sqrt{[0-(-7)]^2+[4-(-2)]^2}\implies JK=\sqrt{(0+7)^2+(4+2)^2} \\\\\\ JK=\sqrt{7^2+6^2} \\\\\\ KL=\sqrt{(9-0)^2+(2-4)^2}\implies KL=\sqrt{9^2+(-2)^2}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0AJ%26%28%7B%7B-7%20%7D%7D%5Cquad%20%2C%26%7B%7B%20-2%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AK%26%28%7B%7B%200%7D%7D%5Cquad%20%2C%26%7B%7B%204%7D%7D%29%5C%5C%5C%5C%0AK%26%28%7B%7B%200%7D%7D%5Cquad%20%2C%26%7B%7B%204%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AL%26%28%7B%7B%209%7D%7D%5Cquad%20%2C%26%7B%7B%202%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AJK%3D%5Csqrt%7B%5B0-%28-7%29%5D%5E2%2B%5B4-%28-2%29%5D%5E2%7D%5Cimplies%20JK%3D%5Csqrt%7B%280%2B7%29%5E2%2B%284%2B2%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AJK%3D%5Csqrt%7B7%5E2%2B6%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AKL%3D%5Csqrt%7B%289-0%29%5E2%2B%282-4%29%5E2%7D%5Cimplies%20KL%3D%5Csqrt%7B9%5E2%2B%28-2%29%5E2%7D)
now... another characteristic of a rhombus is, the diagonals, meet at right-angle, that means KM ⟂ JL
and that simply means, if you get the slope of KM and the slope of JL, the product of their slope is -1
then multiply both slopes, if their product is -1, that means, they're perpendicular to each other, and it IS a rhombus only, then.
now, we know is a parallelogram, so the diagonals will bisect
looking at the picture, the interior angles are not right-angles, and thus is not a rectangle, and is not a square either, due to the same reason
is it a rhombus? well, a rhombus, is a parallelogram, that's "slanted" per se, but regardless of how slanted it may be, the sides are all equal
now, we don't need to check the length of both pairs, just one of the segments of each pair, let's check only then JK and KL, the ones in red in the picture, since each pair of segments are twin, if JK = KL, then that means all sides are equal
now... another characteristic of a rhombus is, the diagonals, meet at right-angle, that means KM ⟂ JL
and that simply means, if you get the slope of KM and the slope of JL, the product of their slope is -1
then multiply both slopes, if their product is -1, that means, they're perpendicular to each other, and it IS a rhombus only, then.