All categories

3 years ago

Please help me out with this

Mathematics

1 answer:

Reil [10]3 years ago

4 0

Answer:

x = 14

Step-by-step explanation:

Chords equidistant from the centre of a circle are equal.

Both chords are 9 units from the centre, thus equidistant and equal, so

x = 7 + 7 = 14

You might be interested in

I bought 5 gallons of gas for 1770 what is the unit price for gas per gallon

Nina [5.8K]

Answer:

<h2>Brainleist!</h2>

Step-by-step explanation:

1770/5 = the unti price

1770 / 5 = <em><u>354</u></em>

3 0

3 years ago

Read 2 more answers

A 25-foot long ladder is propped against a wall at an angle of 18° with the wall. how high up the wall does the ladder reach? ro

Alecsey [184]

Answer

Find out the how high up the wall does the ladder reach .

To proof

let us assume that the height of the wall be x .

As given

A 25-foot long ladder is propped against a wall at an angle of 18° .

as shown in the diagram given below

By using the trignometric identity

$cos\theta = \frac{Base}{Hypotenuse}$

now

$\theta = 18^{\circ}$

Base = wall height = x

Hypotenuse = 25 foot

Put in the trignometric identity

$cos18^{\circ} = \frac{x}{25}$

$cos18^{\circ} = \bar{0.9510565162}$

x = 23.8 foot ( approx)

Therefore the height of the ladder be 23.8 foot ( approx) .

8 0

3 years ago

Read 2 more answers

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

2 years ago

Phillip is restoring a square tabletop he wants to finish the outside edges with a piece of decorative molding what total length

PilotLPTM [1.2K]

Answer:

8 square feet

3 0

3 years ago

2/3 (5 x 4) ÷ 3 + 6/7 I divided 3/2 is 1.5*(20)=30/3=10+1.16=11.16 is that correct not so good in math

Assoli18 [71]

$\frac{2}{3}(5*4):3+ \frac{6}{7} = \\ \\ \frac{2}{3}*20:3+ \frac{6}{7} = \\ \\ \frac{40}{3}:3+ \frac{6}{7} = \\ \\\frac{40}{9}+ \frac{6}{7}= \\ \\ \frac{40*7+6*9}{7*9}= \\ \\\frac{280+54}{63}= \\ \\ \frac{334}{63} = \\ \\ 5 \frac{19}{63} \ \ \ [as \ a \ mixed \ fraction] \\ \\ \approx 5.3 \ \ \ [as \ a \ decimal\ fraction \ to \ the \ nearest \ tenth]$

8 0

3 years ago

Read 2 more answers