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Reptile [31]
3 years ago
12

Please help me out with this

Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer:

x = 14

Step-by-step explanation:

Chords equidistant from the centre of a circle are equal.

Both chords are 9 units from the centre, thus equidistant and equal, so

x = 7 + 7 = 14

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What are the quotient and remainder of (x^5-x^3+-5) divided by (x-2)
pishuonlain [190]

Answer:

x⁴+2x³ +3x²+6x +12 r. \dfrac{19}{x-2}

Step-by-step explanation:

You can do this through synthetic division. It is a shorthand way of dividing polynomials.

First you need to make your divisor equal to zero so you can solve for what goes into the division box:

x - 2 = 0 →     x = 2

The next step is to arrange your polynomials in descending powers. All missing terms, you will put in a zero.

x⁵ - x³ + (-5)   →  x⁵ + 0x⁴- x³ + 0x² + 0x + (-5)

Now you can proceed to synthetic division. Make an upside down division box with the divisor outside and the coefficients of the dividend listed, along with their sign. Leave a space below the divident

+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

Next you bring down the first coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

        +1    

Then you multiply it by the divisor and write the product under the next coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>           +2                                   </u>

        +1    

Next add the column and put the sum below it:

+2 |   +1     0     -1     0     0     -5

    |<u>          +2                                   </u>

        +1    +2

Then multiply again and repeat until you reach the last coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>          +2    +4   +6   +12   +24 </u>

        +1    +2    +3   +6   +12    +19

Now that you have your results, add  in the x and their powers. The powers will start with the highest power but 1 less than the dividend. Since the dividend's highest power is 5, then the quotient's highest power will be 4. Then write it in descending order :

+1x⁴    +2x³    +3x²   +6x   +12   +19

Now the last coefficient is your remainder. So your results will be:

x⁴+2x³ +3x²+6x +12 r. \dfrac{19}{x-2}

7 0
3 years ago
Read 2 more answers
Three less than 5 times a number is less than or equal to 12. If the number is a whole number, what could the number be?:
PIT_PIT [208]

Answer:

D

Step-by-step explanation:

4x2=8

5x2=10

6x2=12

This answer is the closest to 12 but it doesn't go over 12, so this is less than or equal to 12

8 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST Write the equation of the line parallel to the given line and passing through the given point.
Naily [24]

The parallel lines have the same slope.

The slope-intercept form: y = mx + b

m - a slope.

We have 6x + y = 4     |subtract 6x from both sides

y = -6x + 4 → m = -6.

The slope-point form:

y-y_1=m(x-x_1)

We have m = -6 and (-2, 3).

Substitute:

y-3=-6(x-(-2))\\\\y-3=-6(x+2)\\\\y-3=(-6)(x)+(-6)(2)\\\\y-3=-6x-12\qquad|+3\\\\y=-6x-9\qquad|+6x\\\\6x+y=-9

<h3>Answer: 6x + y = -9.</h3>
5 0
3 years ago
Which phrase describes the variable expression 8 n?
soldi70 [24.7K]
The phrase which describes the variable expression 8n is A. the product of 8 and n.
You get a product when you multiply, the quotient is when you divide, the difference is when you subtract, and sum when you add.
6 0
3 years ago
Read 2 more answers
Which of the following products is negative? Select all that apply. *
AlekseyPX

Answer:

  1. (-4)(9)
  2. (6)(-6)

Step-by-step explanation:

1.

(-4)(-9)\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=4\times\:9\\= 36

2.

(-4)(9)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=-4\times\:9\\\\\mathrm{Multiply\:the\:numbers:}\:4\times\:9=36\\=-36

3.

(6)(6)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=6\times\:6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times\:6\\=36

4.

(-6)(-6)\\\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=6\times 6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times\:6\\=36

5.

(6)(-6)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=-6\times 6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times \:6=36\\=-36

8 0
3 years ago
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