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Deffense [45]
3 years ago
9

Nila's soccer practice started at 8:30 A.M. on Saturday morning. The team practiced dribbling for 1 hour and practiced shooting

for 15 minutes. Then they played a scrimmage game for 1 hour and 15 minutes before practice ended. What time was it when Nila's soccer practice ended?
Mathematics
1 answer:
atroni [7]3 years ago
3 0

Answer:

11 pm

Step-by-step explanation:

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Is my answer correct??
Ivanshal [37]

Answer: Last option.

Step-by-step explanation:

For this exercise it is important to remember that a Right triangle is a triangle that has an angle that measures 90 degrees.

By definition, given a Right triangle, if you draw an altitutde from the vertex of the angle that measures 90 degrees (The right angle) to the hypotenuse, the measure of that altitude is the geometric mean between the measures of the two segments of the hypotenuse.

In this case, you have the Right triangle EFH  given in the picture attached.

You can notice that FG goes from the vertex of right angle (\angle F=90\° ) to the hypotenuse EH. Therefore, it divides the hypotenuse into two segments. These are:

EG and GH

Therefore, FG is the geometric mean of the segments EG and GH.

6 0
3 years ago
Evaluate b^2 for b= -4
tekilochka [14]

Answer:

16

Step-by-step explanation:

b^2

Let b= -4

(-4)^2

16

5 0
3 years ago
Read 2 more answers
How to solve for area of triangle where A=67 degrees, b=11yd, and c=24yd
skad [1K]

Use the formula of an area of a tringle:

A=\dfrac{1}{2}bc\sin A

We have b = 11 yd, c = 24 yd and m∠A = 67°

A=\dfrac{1}{2}(11)(24)\sin67^o

\sin67^o\approx0.9205\\\A=(11)(12)(0.9205)=121.506\ yd^2

4 0
3 years ago
I have included a picture of the equation <br><br>​
Alchen [17]

Answer:

it's c , x= 1.5 or -4

2x^2 + 5x - 12 = 0

First factor the left side of the equation

(2x-3)(x+4)=0

Second, set the factors equal to 0

2x-3=0 or x+4=0

 +3  +3       -4  -4

2x=3           -4

divide both side by 2 and you get 3/2 which equals 1.5

x=1.5 or x= -4

3 0
3 years ago
How do I solve this?<br><br> x+1/x-2 &gt; 0
Eduardwww [97]

Answer:

x ∈ (-oo ; - 1) ∪ (+ 2 ; +oo)

Step-by-step explanation:

\frac{x+1}{x-2}>0\\ \\x+1>0=>x>-1\\\\x-2>0=>x>2

x ∈ (+ 2 ; +oo)

x+1x

x ∈ (-oo ; - 1)

x ∈ (-oo ; - 1) ∪ (+ 2 ; +oo)

8 0
3 years ago
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