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MariettaO [177]

3 years ago

6

Marry used ¼ litres of cooking oil this week and left with ½ litres. How much cooking oil Marry has at the beginning of the week

1 answer:

Black_prince [1.1K]3 years ago

5 0

Answer:

3/4

Step-by-step explanation:

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What is the answer for this question

dolphi86 [110]

Answer: 35

Explanation: They originally paid 75$ for the uniforms. We know this because 3000/40 = 75. So the difference would be 75-40, which is 35...

So the answer is 35

6 0

4 years ago

1. Gradpoint. i need the answer ASAP

Stells [14]

Answer:

If we round it to the nearest tenth, our answer would be,

C≈ 17.2 (answer choice C)

Step-by-step explanation:

We will have to use the Pythagorean Theorem to solve this. Since we are not looking for the hypotenuse, but rather the length of one of the legs, we will have to use this,

Let's plug in the values,

Simplify,

Since we know that the opposite of a square is the square root, we are going to apply it.

This tells us that the length of the missing leg would be,

C ≈ 17.2336879396

8 0

3 years ago

Mathematics, Help, not sure about my answer on this one

olga nikolaevna [1]

Answer:

F. 2 1/9

Step-by-step explanation:

Step 1: Substitute q

$r = 3(\frac{1}{3^n} )+2$

When you plug in <em>n</em> = 1, 2, 3:

n(1) = 3

n(2) = 2.11111

n(3) = 2.3333

So our answer is F.

3 0

3 years ago

Match the expression on the left with the correct simplified expression on the right.

andriy [413]

Given: The expression below

$\begin{gathered} (\frac{(3x^3y^4)^3}{(3x^2y^2)^2})^2 \\ (\frac{(3x^4y^2)^4}{(3x^5y^2)^3})^2 \end{gathered}$

To Determine: The matching expression to the given expressions

Solution

Let us simplify each of the expressions using exponents rule

$\begin{gathered} Exponent-Rule1=(a^m)^n=a^{m\times n} \\ Exponent-Rule2=(\frac{a^m}{a^n})=a^{m-n} \end{gathered}$

Applying the exponent rule 1 above to the given expressions

$\begin{gathered} (3x^3y^4)^3=3^3x^{3\times3}y^{4\times3}=27x^9y^{12} \\ (3x^2y^2)^2=3^2x^{2\times2}y^{2\times2}=9x^4y^4 \end{gathered}$ $\begin{gathered} (3x^4y^2)^4=3^4x^{4\times4}y^{2\times4}=81x^{16}y^8 \\ (3x^5y^2)^3=3^3x^{5\times3}y^{2\times3}=27x^{15}y^6 \end{gathered}$

Applying the exponent rule 2

$\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}}=\frac{27x^9y^{12}}{9x^4y^4}=\frac{27}{9}x^{9-4}y^{12-4}=3x^5y^8$ $\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}}=\frac{81x^{16}y^8}{27x^{15}y^6}=\frac{81}{27}x^{16-15}y^{8-6}=3xy^2$

Let us not apply exponent rule 1 above

$(\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}})^2=(3x^5y^8)^2=3^2x^{5\times2}y^{8\times2}=9x^{10}y^{16}$ $(\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}})^2=(3xy^2)^2=3^2x^2y^{2\times2}=9x^2y^4$

Hence, the matching is as shown below

8 0

2 years ago

Nathan and his brother Zach love to play video games. Right now, Nathan's score is 11 less than 2 times Zach's score.-example, i

sashaice [31]

Zach's score, Z, and Nathan's score, N, are related by the formula

2Z-11=N.

This is further explained below.

<h3>What are algebraic expressions?</h3>

Generally, Assume Nathan has a score of N and Zach has a score of Z.

Zach's score is 11 points higher than Nathan's.

It implies,

N equals twice of Z minus 11.

We may format it as follows:

2Z - 11 = N

There are now four possible outcomes for these two brothers' scores:

Zach's score will be determined using algebraic formulas if Nathan's score is 81.

2Z - 11 = 81

2Z = 92

Z = 46

Zach's score will be 61 if Nathan receives a score of 111.

Zach's score will be 121 if Nathan's score is 231 or higher.

Zach's score will be 456 if Nathan's score is 901.

The formula 2Z - 11 = Z is a rule that connects Nathan's and Zach's scores.

Visit to learn more about algebraic expressions.

brainly.com/question/953809

#SPJ1

5 0

1 year ago