Solve the equation, round the answers to two decimal places. <br> 4=e^0.08t

Solve the equation using the distributive property and properties of equality. -5(a+3)=-55 What is the value of a? A.)-14 B.) -8

Colt1911 [192]

Answer:

C) 8

Step-by-step explanation:

-5(a+3)=-55

a+3=-55/-5

a+3=11

a=11-3

a=8

4 0

3 years ago

I WILL GIVE BRAINLIEST! Please answer these 5 questions correctly! (NO INCORRECT ANSWERS LINKS WILL BE REPORTED NO TROLL ANSWERS

BlackZzzverrR [31]

Answer:

1.) 4a + 55

2.) 88m + 24k - 55

4.) b and d

5.) b and d

6.) a

7.) 3x + x + 10

Step-by-step explanation:

Hope this helped :)

5 0

2 years ago

Please simplify this expression.<br> 1 + 4.25n + 32p – 3 + (–2p) + 54n

nata0808 [166]

Answer:

58.25n+30p-2

Step-by-step explanation:

Given the expression as;

1 + 4.25n + 32p – 3 + (–2p) + 54n

collect like terms

1-3+4.25n+54n+32p-2p

-2+58.25n+30p

58.25n+30p-2

I have copied one brainly user's answer, sorry for that...

However, hope it helps you!!!

5 0

3 years ago

Read 2 more answers

a hotel with 75 rooms has 45 for doubles and 30 singles. singles can be booked in any room, but reservations for two or more peo

Hatshy [7]

Answer:

y = 75 - x

Step-by-step explanation:

From the question, we are given variables, and then we can see that

when x = 75 then y = 0

when x = 30 then y = 45

Finding the difference, we have

slope(m) = (45 - 0) / (30 - 75)

slope(m) = 45 / -45

slope(m) = -1

Next, we use the calculated m, to find b, using the formula

y = mx + b

0 = -1 * 75 + b

0 = -75 + b

b = 75

And finally, to get the needed equation, we say that

so y = mX+c

So that

y = -1 * x + 75

y = -x + 75

or y = 75 - x

6 0

2 years ago

Suppose we are interested in analyzing the weights of NFL players. We know that on average, NFL players weigh 247 pounds with a

tigry1 [53]

Answer:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

Step-by-step explanation:

For this case we have the following data given:

$\bar X =237$ represent the sample mean

$\sigma = 47$ represent the population deviation

$n =30$ represent the sample size selected

$\mu_0 = 247$ represent the value that we want to test.

The standard error for this case is given by:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

For the 90% confidence the value of the significance is given by $\alpha=1-0.9 = 0.1$ and $\alpha/2 = 0.05$ so we can find in the normal standard distribution a quantile that accumulates 0.05 of the area on each tail and we got:

$z_{\alpha/2}= 1.64$

And the margin of error would be:

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

The confidence interval for this case would be given by:

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

Replacing into formula (b) we got:

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is lower than 247 pounds, the system of hypothesis would be:

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

P-value

Since is a left tailed test the p value would be:

$p_v =P(z$

Conclusion

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

5 0

2 years ago

Solve the equation, round the answers to two decimal places. 4=e^0.08t