Answer:
Question 9: Variables: (smallest) s, q, r (largest)
Question 10: 5 whole numbers (7, 8, 9, 10, and 11)
Step-by-step explanation:
For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>
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For question 10, it states 
. This can be split into 
and 
. When x is 12 in the first equation then 
and when x is 6 in the second equation 
(0.5 is also 
). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11 or 5 whole numbers.
The formula for area of a circle is (pi)*radius^2
Radius is half of diameter so the radius is 2.
2 squared is 4, then multiply by pi to get an answer of 4(pi) or 12.56.
Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
Answer:
AOC = 124°
Step-by-step explanation:
Angle on a straight line is 180°, therefore, the sum of the three angles shown is 180;
This can be written like so:
(3x + 94) + (x + 30) + (2x - 4) = 180
This equation can be solved to find x:
6x + 120 = 180
6x = 180 - 120
6x = 60
x = 10
AOC = 3(10) + 94
= 30 + 94
= 124
5.
f(K) = D^3 => f(25) = 125 => 25 * t = 125 ( because K is directly proportional with D^3 )=> t = 125 / 25 => t = 5 => f(25) = 25 * 5 => K * 5 = D^3 ;
6.
f(L) = F^3 => f(2) =3^3 =>f(2) = 27 => 2 / t =27 => t = 2 / 27 => t = 0.074 => f(2) = 2 / 0.074 => K / 0.074 = F^3 ;
