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3 years ago

Can someone answer #10 please?

Mathematics

1 answer:

n200080 [17]3 years ago

8 0

Not sure of the question...1 missing vs 8 found
or 1 missing vs 9 piece puzzle

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Solve for x- round to the nearest tenth- Trigonometry

Rashid [163]

Answer:

sin26=11/X

0.438371146789×x=11

X. = 11/0.438371146789

X=25.09289235975

4 0

3 years ago

Factor the polynomial.

Iteru [2.4K]

3x4+6x3+9x2
Factored: (3x2)(x2+2x+3)

Answer:
C) 3x2(x2+2x+3)

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

A major credit card company has determined that customers charge between $100 and $1100 per month. If the monthly amount charged

Alexxx [7]

Answer:

a) $E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600$

b) First we need to calculate the variance given by this formula:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33$

And the deviation would be:

$Sd(X) = \sqrt{83333.33}= 288.675$

c) $P(600 < X< 889) = P(X$

And using the cdf we got:

$P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289$

d) $P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578$

Step-by-step explanation:

For this case we define the random variable X who represent the customers charge, and the distribution for X on this case is:

$X \sim Unif (a= 100, b=1100)$

Part a

For this case the average is given by the expected value and we can use the following formula:

$E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600$

Part b

First we need to calculate the variance given by this formula:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33$

And the deviation would be:

$Sd(X) = \sqrt{83333.33}= 288.675$

Part c

For this case we want to find the percent between 600 and 889, so we can use the cumulative distribution function given by:

$F(x) = \frac{X -100}{1100-100}= \frac{x-100}{1000}, 100 \leq X \leq 1100$

And we can find this probability:

$P(600 < X< 889) = P(X$

And using the cdf we got:

$P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289$

Part d

$P(311 < X< 889) = P(X$

And using the cdf we got:

$P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578$

6 0

3 years ago

mash [69]

Answer:

Step-by-step explanation:

Because you left one pence then it is 9-1=8

3 0

4 years ago

Read 2 more answers

Avannah drove 716 miles on Monday. She drove another 572 miles on Tuesday. About how many miles did she drive altogether?

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

1,288 =1,300?

4 0

3 years ago

Read 2 more answers