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timama [110]
3 years ago
7

On the last three chemistryexams a student scored 87, 88​, and 89. What score must the student earn on the next exam to have an

average of at least​ 90?
The student must score at least ___%.
Mathematics
1 answer:
hammer [34]3 years ago
4 0

Answer:96%

Step-by-step explanation: 4 x 90 = 360, 87 + 88 + 89 = 264, 360 - 264 = 96

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1/8

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Determine if jk and lm are parallel, perpendicular, or neither j(1,9),k(7,4),l(8,13),m(-2,1)
photoshop1234 [79]

Answer:

"perpendicular"

Step-by-step explanation:

We need to find slope (m) of both line JK and LM

Slope has formula:

m=\frac{y_2-y_1}{x_2-x_1}

Lets find slope of JK:

m=\frac{4-9}{7-1}\\m=-\frac{5}{6}

Lets find slope of LM:

m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{1-13}{-2-8}\\m=\frac{6}{5}

we know if we multiply two lines' slope and get -1, they are perpendicular. Let's check:

-\frac{5}{6}*\frac{6}{5}=-1

Hence, they are perpendicular

4 0
3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
Colt1911 [192]

Answer: 34%

Step-by-step explanation:

According to the Empirical rule,

About 68% of the population lies with in one standard deviation from the mean.

i.e. About  34% of the population lies above one standard deviation from the mean .

and About 34% of the population lies below one standard deviation from the mean.

Given : The distribution of the number of daily requests is bell-shaped ( i.e. Normally distribution) and has a mean of 60 and a standard deviation of 11.

i.e. \mu=60\ \ \sigma=11

Using the Empirical Rule rule,  34% of the population of lightbulb replacement requests lies above one standard deviation from the mean .

i.e. About 34% of the population of lightbulb replacement requests lies between \mu and \mu+\sigma

i.e. About   34% of the population of lightbulb replacement requests lies between 60 and 60+11

i.e. About  34% of the population of lightbulb replacement requests lies between 60 and 71

Hence, the approximate percentage of lightbulb replacement requests numbering between 60 and 71 = 34%

4 0
2 years ago
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