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marusya05 [52]
3 years ago
10

There are 5 chemistry, 6 physics, and 7 math teachers in a school. if 3 teachers are selected randomly, find the probability tha

t at least one is a math teacher.
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
6 0
77.2%

To find the probably and at least on you must find the probability of none and subtract from one.

The probability of none can be found like so:

(5+6 over 5+6+7)^3 = .228

1 - .228 = .772

Hope this helps!
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Here’s the next problem:)
horsena [70]

Answer:

disagree

Step-by-step explanation:

toa=opposit over adjacent= 12/9

tan(x)=12/9

tan^-1=12/9

x= 53.1

6 0
3 years ago
Read 2 more answers
Rachel rolls two number cubes, each with sides that are labeled 1 to 6. What is the probability that one number cube lands on a
Alex Ar [27]

Answer:

4/6. out of 1 2 3 4 5 6 only 3 number are even.but it says lands on 1 and the other lands on even. so 3 +1 = 4. sorry if it doesnt make sense

5 0
3 years ago
Drawing Conclusions
maksim [4K]

Answer:

Some of the Exponents = -2 that is true, not 2.

Step-by-step explanation:

Let's check one at a time.

(a)The 6 without an exponent is equivalent to the 6 having a 0 exponent.

6^{0} =1 and 6^{1} = 6 (no exponent. 6 \neq 1 therefore this statement is False.

(b)The sum of the exponents is -2.

let's check , if the base is same we can add the exponents that is the exponent rule.(well established).

if we add exponents in the given expression we get.

6^{1} 6^{0} 6^{3} =6^{1+0+(-3)} =6^{-2}, therefore we can see that the sum of the exponents = -2 this is true.

(c) An equivalent expression is 65.6-7, lets evaluate our above expression, it is equal to \frac{1}{36} which we can see that \frac{1}{36}  \neq 65.6-7 ,therefore this statement is false as well.

3 0
3 years ago
PLEASE HELP ME IN FINANCE!!
borishaifa [10]

Answer:

A

Step-by-step explanation:

if we had a economic turn down, basically people would lose money, so that means the consumers, so the producers will have a bunch of left over products because the people can't afford to buy as much, which means the company loses money, which means the employees must be let go of so the business doesn't go out of business

7 0
3 years ago
Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.
Aleks [24]

Answer:

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

Step-by-step explanation:

The actual Series is::

\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}

The method we are going to use is comparison method:

According to comparison method, we have:

\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}

Now:

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty}  \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

\sum_{n=1}^{inf}\frac{1}{n^p}

if p>1 then series converges. In oue case we have:

\sum_{n=1}^{inf}b_n=\frac{1}{n^4}

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

5 0
3 years ago
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