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adell [148]
3 years ago
11

Wake up to reality

Mathematics
1 answer:
Sphinxa [80]3 years ago
6 0

Answer:

What do I answer?.......

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What is the value of x in the equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7Dx%20-%5Cfrac%7B2%7D%7B3%7D" id="Te
SVEN [57.7K]

Answer:

x= 200

Step-by-step explanation:

The given equation is:

1/5 x - 2/3 y = 30

The value of y is 15

Put the value of y in the given equation:

1/5 x - 2/3(15) = 30

1/5 x- 10 = 30

Take the L.C.M of the denominator

x-50/5 = 30

Move the denominator to the R.H.S

x-50 = 30*5

x-50 = 150

Combine the like terms

x= 150+50

x = 200

The value of x is 200...

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3 years ago
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xxMikexx [17]

Answer:

I hope this helps!!!!

Step-by-step explanation:

the answer is in the picture!

3 0
3 years ago
Janie receives an allowance of $3 per week.
inn [45]
Janie receives an allowance of $3 per week.
In addition, she can earn $2 for each chore she does.
This week, she wants to earn enough money to buy a CD for $13.
Janie can do fractions of chores.

Write an inequality to determine the number of chores Janie must do this week to earn enough money to buy a CD.
13 <= 2c + 3 is the inequality.

Hope this helps!
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3 years ago
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Which equation finds the area of a square with a side length of 5 n Superscript 4 units?
Oduvanchick [21]

Answer:

area of a square is S^2

s = 5n^4

area = (5n^4)^2 = 25n^8

Step-by-step explanation:

4 0
3 years ago
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Find the equation of the inverse.<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%7B2%7D%5E%7Bx%20%2B%205%7D%20%20-%206" id="TexF
Contact [7]

Find the equation of the inverse.

y =  {2}^{x + 5}  - 6

we have

y=\mleft\{2\mright\}^{\mleft\{x+5\mright\}}-6

step 1

Exchange the variables

x for y and y for x

x=\{2\}^{\{y+5\}}-6

step 2

Isolate the variable y

(x+6)=2^{(y+5)}

apply log both sides

\begin{gathered} \log (x+6)=(y+5)\cdot\log (2) \\ y+5=\frac{\log (x+6)}{\log (2)} \\  \\ y=\frac{\log(x+6)}{\log(2)}-5 \end{gathered}

step 3

Let

f^{(-1)}(x)=y

therefore

the inverse function is

f^{(-1)}(x)=\frac{\log(x+6)}{\log(2)}-5

7 0
1 year ago
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