
Notice that

So as

you have

. Clearly

must converge.
The second sequence requires a bit more work.

The monotone convergence theorem will help here; if we can show that the sequence is monotonic and bounded, then

will converge.
Monotonicity is often easier to establish IMO. You can do so by induction. When

, you have

Assume

, i.e. that

. Then for

, you have

which suggests that for all

, you have

, so the sequence is increasing monotonically.
Next, based on the fact that both

and

, a reasonable guess for an upper bound may be 2. Let's convince ourselves that this is the case first by example, then by proof.
We have


and so on. We're getting an inkling that the explicit closed form for the sequence may be

, but that's not what's asked for here. At any rate, it appears reasonable that the exponent will steadily approach 1. Let's prove this.
Clearly,

. Let's assume this is the case for

, i.e. that

. Now for

, we have

and so by induction, it follows that

for all

.
Therefore the second sequence must also converge (to 2).
Answer:
b
Step-by-step explanation:
give me brainelest pls
Answer: 4^-2
Step-by-step explanation:
the Bases stays the same the powers changes to negative -2 because you are stubtracting 6-8 which gives you negative -2.
If you have these conditions:
1. (r ,theta) where r > 0
<span>2. (r, theta) where r < 0
</span>
The solution would be:
<span>r = sqrt(x^2 + y^2)
t = arctan(y/x)
r = sqrt(12 + 4) = sqrt(16) = +/- 4
t = arctan(2 / -2sqrt(3)) = arctan(-1 / sqrt(3)) = 5pi/6 , 11pi/6
1)
r > 0
(4 , 11pi/6)
2)
r < 0
(-4 , 5pi/6)
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
It will double in size, as M x M x M x M is simply just 3 changeable values. When we change 4 numbers of a prism (3 changed values ) to all 4 we have a S4 value to the volume, But we didnt do this, applying x 4 to either measurement it can only increase the volume by x 2. We had a one change value SF4 so we have SF 2= double. That means if we have two change value value SF4 we have 3 = 3 x total increase, if we have a three input change by SF4 we can increase size to 4x total increase.
Step-by-step explanation: