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OLga [1]
4 years ago
12

Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show the for

mal charges of all atoms in the correct structure. To change the symbol of an atom, double-click on the atom and enter the letter of the new atom for:SeO2 and CO2?3

Chemistry
1 answer:
Alexus [3.1K]4 years ago
5 0

Answer:

See explanation below

Explanation:

In this case, let's see both molecules per separate:

In the case of SeO₂ the central atom would be the Se. The Se has oxidation states of 2+, and 4+. In this molecule it's working with the 4+, while oxygen is working with the 2- state. Now, how do we know that Se is working with that state?, simply, let's do an equation for it. We know that this molecule has a formal charge of 0, so:

Se = x

O = -2

x + (-2)*2 = 0

x - 4 = 0

x = +4.

Therefore, Selenium is working with +4 state, the only way to bond this molecule is with a covalent bond, and in the case of the oxygen will be with double bond. See picture below.

In the case of CO₂ happens something similar. Carbon is working with +4 state, so in order to stabilize the charges, it has to be bonded with double bonds with both oxygens. The picture below shows.

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An excess of sodium carbonate, Na2CO3, in solution is added to a solution containing 15.71 g CaCl2. After performing the experim
OlgaM077 [116]

Answer:

93.15 %

Explanation:

We have to start with the chemical reaction:

CaCl_2~+~Na_2CO_3~->~CaCO_3~+~NaCl

Now, we can balance the reaction:

CaCl_2~+~Na_2CO_3~->~CaCO_3~+~2NaCl

Our initial data are the 15.71 g of CaCl_2, so we have to do the following steps:

1) <u>Convert from grams to moles of CaCl_2 using the molar mass (110.98 g/mol).</u>

2) <u>Convert from moles of CaCl_2 to moles of CaCO_3 using the molar ratio. ( 1 mol CaCl_2= 1 mol of CaCO_3).</u>

3) <u>Convert from moles of CaCO_3 to grams of CaCO_3 using the molar mass. (100 g/mol).</u>

15.71~g~CaCl_2\frac{1~mol~CaCl_2}{110.98~g~CaCl_2}\frac{1~mol~CaCO_3}{1~mol~CaCl_2}\frac{100~g~CaCO_3}{1~mol~CaCO_3}=14.16~g~CaCO_3

Finally, we can calculate the yield percent:

%~=~\frac{13.19~g~CaCO_3}{14.16~g~CaCO_3}*100=93.15~%

I hope it helps!

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4 years ago
Why do the ocean currents move from the equator towards the poles?
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Hey there!

The reason why <span>ocean currents move from the equator towards the poles are because the wind push the water's away from the equator and toward the poles, so pretty much, let's blame this on the wind, it's the wind's fault not ours. But yes, your correct answer to this question above would be of that the wind's push the water's away from the equator and to the poles.

Hope this helps you buddy!</span>
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The answer is inversely

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