The amount of heat required to change 25 grams of water into steam is 56425 joules or 13500 calories.
PVA glue or elmers glue PVA Glue does all the basics fairly well, and has all the binding ability you'd expect from an adhesive.
The closeness of a measurement to its true value is a measure of its accuracy. This term is the degree of which a certain measurement conforms to the correct value or the standard value. It is not the same with the term precision. Precision, on the other hand, is a measure used to characterize the closeness of the data measured.
Covalent bonds are between two non-metals. Hydrogen and oxygen are non-metals. Hence is is, "yes, hydrogen and oxygen are nonmetals."
For the future, you might want to look at some videos to help you! :) (Tyler DeWitt is a really good chem you-tube teacher!)
The answer is: [B]: 1.89 * 10²³ .
____________________________________________________
PV = nRT ; is the equation for "STP" conditions; that is, the "ideal gas equation" .
_______________________________________________
i.e. when Pressure, "P" = 1.00 atm;
Temperature, "T" = 273 K;
_____________________________________
R = the ideal gas constant = ((0.08206 L-atm/K-mol)
n = number of moles;
___________________________________
So, we plug in our known values:
______________________________________________
<span>(1.00atm) (7.02L) = ("n" mol) (0.08206 L-atm/K-mol) (273K); </span>
<span>_____________________________________________
</span>→ 7.02 L·atm = (? mol) (22.4 L·<span>atm/mol) .
</span>
(Note that t<span>he Molar Volume of a gas at STP is a constant using Avogadro's value of </span>22.4 L / mol. 1 mol of any ideal gas at STP occupies 22.4 L. An ideal gas takes the shape of its container)..
<span>_______________________________________________________
</span> → Divide EACH side of the equation by "(22.4 L·atm/mol)" ;
________________________________________________
→ 7.02 L·atm / = ("n" mol) (22.4 L·atm/mol) ;
_________________________________________________
→ 7.02 L·atm / (22.4 L·atm/mol) =
[("n" mol) (22.4 L·atm/mol)]/(22.4 L·atm/mol);
______________________________________________________
<span>to get:
_________________________________________________
</span>→ n = <span>0.313 mol ;
</span>_____________________________________________________
Note: 1 mole = 1 mol = 6.022 * 10²³ molecules.
____________________________________________
→ So, 0.313 mol Cl₂ (g) molecules * [(6.022 * 10²³ molecules) / (1 mol)] =
___________________________________________________________
→ [(0.313) * (6.022 *10²³) ] molecules of Cl₂ (g) ;
___________________________________________________________
→ = 1.88 * 10²³ molecules of Cl₂ g ;
___________________________________________________________
→ which most closely corresponds with answer choice:
___________________________________________________________
[B]: 1.89 * 10²³ .
___________________________________________________________
