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3 years ago

For each equation, tell whether its graph is a horizontal or verticle line

Mathematics

1 answer:

Molodets [167]3 years ago

4 0

Y= something is horizontal

x= something is vertical

1 hor
2 ver
3 hor
4 ver

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What is the circumference of this circle, in centimeters? Use for .

Orlov [11]

Answer:

what is the circle.

Circumference is diameter x 3.14.

Diameter is the whith of a circle.

Ex. diameter = 4

4 x 3.14 = 12.6cm.

Step-by-step explanation:

5 0

3 years ago

Justin earned $50 mowing lawns and $34 washing cars. He wants to divide his money into 3 equal accounts. How much will he put in

castortr0y [4]

Answer:28

Step-by-step explanation:

Mowing 50

Car washing 34

Total amount 84

Now divide by 3 accounts 84/3=28

8 0

3 years ago

Simplify (3x + 5) + (2x - 9) - (4x + 3

Law Incorporation [45]

If you would like to simplify (3 * x + 5) + (2 * x - 9) - (4 * x + 3), you can do this using the following steps:

(3 * x + 5) + (2 * x - 9) - (4 * x + 3) = 3 * x + 2 * x - 4 * x + 5 - 9 - 3 = 1 * x - 7 = x - 7

The correct result would be x - 7.

4 0

3 years ago

Read 2 more answers

A quantity with an initial value of 600 decays exponentially at a rate of

Snowcat [4.5K]

Answer:

The value of the quantity after 87 months will be of 599.64.

Step-by-step explanation:

A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.

This means that the quantity, after t periods of 6 years, is given by:

$Q(t) = 600(1 - 0.0005)^{t}$

What is the value of the quantity after 87 months, to the nearest hundredth?

6 years = 6*12 = 72 months

So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).

$Q(t) = 600(1 - 0.0005)^{t}$

$Q(1.2083) = 600(1 - 0.0005)^{1.2083} = 599.64$

The value of the quantity after 87 months will be of 599.64.

8 0

3 years ago

I DONT KNOW THESE! HELP!

kkurt [141]

Answer:

20. x = 5, y = -2

21. x = 11, y = 12

22. x = 22, y = 11

23. x = 11, y = 10

Step-by-step explanation:

20. Opposite sides in the parallelogram are congruent, so

$2y+18=3x-1\\ \\6x-3=17-5y$

Solve this system of two equations:

$\left\{\begin{array}{l}2y-3x=-19\\ \\6x+5y=20\end{array}\right.$

Multiply the first equation by 2 and add two equations:

$2(2y-3x)+6x+5y=2\cdot (-19)+20\\ \\4y-6x+6x+5y=-38+20\\ \\9y=-18\\ \\y=-2$

Substitute it into the first equation:

$2\cdot (-2)-3x=-19\\ \\-3x=-19+4\\ \\-3x=-15\\ \\x=5$

21. Opposite angles in the parallelogram are congruent, so

$11x+5=10y+6$

Consecutive angles are supplementary, so

$6x-y+11x+5=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}11x-10y=1\\ \\17x-y=175\end{array}\right.$

From the second equation

$y=17x-175$

Substitute it into the first equation:

$11x-10(17x-175)=1\\ \\11x-170x+1750=1\\ \\-159x=-1749\\ \\x=11\\ \\y=17\cdot 11-175=187-175=12$

22. Opposite angles in the parallelogram are congruent, so

$2x-5=3y-12$

Consecutive angles are supplementary, so

$2x-5+7y+x=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-3y=-7\\ \\3x+7y=185\end{array}\right.$

From the first equation

$x=-3.5+1.5y$

Substitute it into the second equation:

$3(-3.5+1.5y)+7y=185\\ \\-10.5+4.5y+7y=185\\ \\-105+45y+70y=1,850\\ \\115y=1,850+105\\ \\115y=1,955\\ \\y=17\\ \\x=-3.5+1.5\cdot 17=22$

23. Opposite sides in the parallelogram are congruent, so

$2x+9=4y-9\\ \\3x-5=2y+8$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-4y=-18\\ \\3x-2y=13\end{array}\right.$

Multiply the second equation by 2 and subtract it from the first equation:

$2x-4y-2(3x-2y)=-18-2\cdot 13\\ \\2x-4y-6x+4y=-18-26\\ \\-4x=-44\\ \\x=11$

Substitute it into the first equation:

$2\cdot 11-4y=-18\\ \\-4y=-18-22\\ \\-4y=-40\\ \\y=10$

3 0

3 years ago