Trigonometry
2 answers:
55° is equal to 0.9599 radians.
Step-by-step explanation:
Step 1:
If an angle is represented in degrees, it will be of the form x°.
If an angle is represented in radians, it will be of the form radians.
To convert degrees to radians, we multiply the degree measure by .
For the conversion of degrees to radians,
the degrees in radians = (given value in degrees)().
Step 2:
To convert 50°,
radians.
So 55° is equal to 0.9599 radians.
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Answer:
The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.
Step-by-step explanation:
Denote the different kinds of drivers as follows:
L = low-risk drivers
M = moderate-risk drivers
H = high-risk drivers
The information provided is:
P (L) = 0.50
P (M) = 0.30
P (H) = 0.20
Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.
The combination of 4 new drivers that satisfy the condition that there are at least two more high-risk drivers than low-risk drivers is:
S = {HHHH, HHHL, HHHM, HHMM}
Compute the probability of the combination {HHHH} as follows:
P (HHHH) = [P (H)]⁴
= [0.20]⁴
= 0.0016
Compute the probability of the combination {HHHL} as follows:
P (HHHL) = × [P (H)]³ × P (L)
= 4 × (0.20)³ × 0.50
= 0.016
Compute the probability of the combination {HHHM} as follows:
P (HHHL) = × [P (H)]³ × P (M)
= 4 × (0.20)³ × 0.30
= 0.0096
Compute the probability of the combination {HHMM} as follows:
P (HHMM) = × [P (H)]² × [P (M)]²
= 6 × (0.20)² × (0.30)²
= 0.0216
Then the probability that these four will contain at least two more high-risk drivers than low-risk drivers is:
P (at least two more H than L) = P (HHHH) + P (HHHL) + P (HHHM)
+ P (HHMM)
= 0.0016 + 0.016 + 0.0096 + 0.0216
= 0.0488
Thus, the probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.
We have to identify the rational function among the given functions.
Rational function is a function that is the ratio of two polynomials. It is rational because one polynomial is divided by the other polynomial, like a ratio.
1. Consider the first function , since it is not a function that is the ratio of two polynomials. So, it is not a rational function.
2. Consider the second function , since it is not a function that is the ratio of two polynomials. So, it is not a rational function.
3. Consider the third function , since it is not a function that is the ratio of two polynomials. So, it is not a rational function.
4. Consider the fourth function , since it is a function that is the ratio of two polynomials (x+2) and (5x). So, it is a rational function.
So, Option D is the correct answer.