Ask question

Ask question

All categories

3 years ago

8

In what ways does adding a constant or coefficient to a quadrationc affect the graph

1 answer:

Roman55 [17]3 years ago

3 0

Hope this helps <span>1) </span><span>Equations with negative values for a</span><span> produce graphs that open down and equations with a positive values for a</span> produce graphs that open up.

<span>2)<span> </span></span><span>As the absolute value of a gets larger our graphs become more narrow (they shoot towards positive or negative infinity faster). This is more interesting than it might appear. If you consider the second derivative of any quadratic it will be the a</span><span> value. The second derivative represents acceleration, so the larger the a value the faster the increase of velocity and accordingly a quicker progression towards positive or negative infinity. Check this out in graphing calculator, press play to vary the value of a from -20 to 20. Notice that when the value of a approaches zero, the approximates a line, and of course when a is 0 we have the line y</span><span> = 2x</span><span> – 1.</span>

You might be interested in

Two trains are 500 miles apart when they first enter a collision course. If, after two hours, the distance between them is 300 m

MrRissso [65]

Answer:

The faster train goes 60mph

Step-by-step explanation:

s= speed

s+20 is the faster train.

Then you are given:

200/s+s+20=2

200=2*(2s+20)

4s+40=200

4s=160

s=40 is the slower train

40+20= speed of faster one

s=60 ;)

6 0

3 years ago

Find the modulus of the complex number 6-2i

Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

Step-by-step explanation:

Given the number

$6-2i$

We know that

$z = x + iy$

where x and y are real and $\sqrt{-1}=i$

The modulus or absolute value of z is:

$|z|\:=\sqrt{x^2+y^2}$

Therefore, the modulus of $6-2i$ will be:

$z=6-2i$

$z=6+(-2)i$

$|z|\:=\sqrt{x^2+y^2}$

$|z|\:=\sqrt{6^2+\left(-2\right)^2}$

$=\sqrt{6^2+2^2}$

$=\sqrt{36+4}$

$=\sqrt{40}$

$=\sqrt{2^2}\sqrt{2\cdot \:5}$

$=2\sqrt{2\cdot \:5}$

$=2\sqrt{10}$

Therefore, the modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

3 0

2 years ago

What is the average of pi

Oksanka [162]

The average of pi is 3.14 and is an irrational #

5 0

2 years ago

What 1,045 to the nearest thousands

faltersainse [42]

1,045 to the nearest thousands would be <u>1,000</u> because you must round down since there are no numbers close enough to round up.

8 0

3 years ago

Read 2 more answers

Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters. The radius of sphere A is multiplied by

Tamiku [17]

Answer:

7/8

Step-by-step explanation:

Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters.

WE need find which factor is multiplied with radius of sphere A to produce the radius of sphere B

Diameter of sphere B is 42

Radius = diameter /2

Radius = 42/2= 21

Radius of sphere B = 21

RAdius of sphere A times x= radius of sphere B

24 * x= 21

Divide by 24 on both sides

x= 21/ 24

divide top and bottom by 3

x= 7/ 8

5 0

2 years ago

Read 2 more answers