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neonofarm [45]
1 year ago
5

A. in terms of the number of marked elk, what is the relative frequency of male elk, female elk, adult elk, and baby elk? write

your answers as simplified fractions.
b. based on the data, how many male, female, adult, and baby elk do you predict are in the park?
Mathematics
1 answer:
mash [69]1 year ago
4 0

The relative frequency of the marked elks are:

  • Male Elk  = 7/30
  • Female Elk = 4/15
  • Adult Elk= 173/450
  • Baby Elk = 26/22

<h3>How to determine the relative frequency?</h3>

From the complete question, we have:

  • Male = 105
  • Female = 120
  • Adult =  173
  • Baby = 52
  • Total = 450

The relative frequency of each is then calculated as:

Male Elk = 105/450

Male Elk  = 7/30

Female Elk = 120/450

Female Elk = 4/15

Adult Elk= 173/450

Baby Elk = 52/450

Baby Elk = 26/22

<h3>The number of Elks in the park</h3>

Using the data in (a), we can conclude that:

There are 105 male, 120 female, 173 adult, and 26 baby in the park

Read more about frequency table at:

brainly.com/question/1094036

#SPJ1

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Only male crickets chirp. They chirp at different rates depending on their species and the temperature of their environment. Sup
bezimeni [28]

Answer:

4920

7084800

2585952000

Step-by-step explanation:

82 chirps = 1 minute

We have 60 minutes in one hour, so 82 x 60 =4920 chirps in one hour

In 24 hours we have 60x24 = 1440 minutes and in one minutes we have 4920 chirps,

Therefore 4920 x 1440 mins =7084800 chirps in one day .

There are 365 days in a year and in one day the cricket chirps 7084800, so 365 days x 7084800 = 258595200 chirps in a year

6 0
3 years ago
X^4 − 3x^2 − 90 x= -3
Ahat [919]

Answer:

-36

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

x⁴ - 3x² - 90

x = -3

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                                                                                                  (-3)⁴ - 3(-3)² - 90
  2. Exponents:                                                                                                        81 - 3(9) - 90
  3. Multiply:                                                                                                             81 - 27 - 90
  4. Subtract:                                                                                                            54 - 90
  5. Subtract:                                                                                                            -36
8 0
3 years ago
The weight of an apple is 150g, rounded to the nearest 5g. what is the lower bound and upper bound?
Aneli [31]

The lower bound is 147.5 and the upper bound is 152.5.

Given the weight of an apple 150 g rounded to the nearest 5g.

We have to find lower bound and upper bound.

Lower bound is an element less than or equal to all the elements in a given set.

Upper bound is an element greater than all the elements in a given set.

Lower bound= Number 1- (Number nearest to  which number 1 is rounded)/2

Upper bound=Number 1+(number nearest to which number 1 is rounded)/2

Weight of an apple =150 g

Lower bound=150-5/2

=150-2.5

=147.5

Upper bound=150+5/2

=150+2.5

=152.5

Hence the lower bound is 147.5 and upper bound is 152.5.

Learn more about lower and upper bounds at brainly.com/question/15408313

#SPJ4

4 0
2 years ago
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