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Artyom0805 [142]
4 years ago
10

What is the missing number in 12,24,72,288

Mathematics
1 answer:
Ronch [10]4 years ago
5 0
12*2=24
 24*3=72
 72*4=288
 n*(x+1)
288*(4+1)
288*5=1440
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Pls Help Choose the correct word to complete the statement: If BC intersects circle A only at point B, and mCBA = 90°, then CB i
cricket20 [7]

Line CB touches circle A only at one point (point B), hence CB is a tangent.

<h3>What is a circle?</h3>

A circle is the locus of a point such that its distance from a fixed point (center) is always constant.

When a line intersects a circle in exactly one point the line is said to be tangent to the circle

Hence since Line CB touches circle A only at one point (point B), hence CB is a tangent.

Find out more on circle at: brainly.com/question/24375372

7 0
3 years ago
Triangle ABC has coordinates A(-2, -3), B(1, 1), and C(2, -1). If the triangle is translated 4 units up, what are the coordinate
DochEvi [55]

Answer:

The coordinates of point A' will be: A'(-2, 0)

Step-by-step explanation:

We know that a translation is basically a transformation that occurs when an object is moved from one place to another place.

Translation does not change the size, orientation, or shape of the original object.

Translating a point P(x, y) 4 units up means we need to add to use P'(x, y+4), that is adding 4 units to the y-coordinate of the point P'(x, y).

Now we have to translate the triangle 4 units up. So, use the formula

P(x, y) → P'(x, y + 3)

Thus, the coordinates of point A' will be:

A(-2, -3) → A'(-2, -3+3) → A'(-2, 0)

Therefore, the coordinates of point A' will be: A'(-2, 0)

8 0
3 years ago
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guajiro [1.7K]

Answer:

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3 0
3 years ago
What is the area of the sector with a central angle of 49° and a radius of 11 cm? Use 3.14 for pi and round your final answer to
olga_2 [115]

Answer:

\boxed{\text{51.71 cm}^{2}}

Step-by-step explanation:

If the angle θ is in radians, the formula for the area (A) of a sector of a circle is

A = ½r²θ

If θ is in degrees

A = \dfrac{1}{2}r^{2}\theta \times \dfrac{\pi \text{ rad}}{180^{\circ}}= \pi r^{2}\times\dfrac{\theta }{360}

Data:

θ = 49°

r = 11 cm

Calculation:

\begin{array}{rcl}A& = &3.14\times 11^{2}\times\dfrac{49}{360}\\\\ & = &3.14 \times 121 \times 0.1361\\ & = & \mathbf{51.71}\\\end{array}\\\text{The area of the sector is }\boxed{\textbf{51.71 cm}^{2}}

4 0
3 years ago
The circle below is centered at the point (-1,3) and has a radius of length 4
Snowcat [4.5K]
(x-h)^2 + (y-k)^2 = r^2 where h & k are the x,y values of the center point

(x + 1)^2 + (y-3)^2 = 4^2
<span>(x + 1)^2 + (y-3)^2 = 16</span>
6 0
3 years ago
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