Question

What is the value of x if 9x^-1 - 2 = 25

Answer 1

Answer: $x=\frac{1}{3}$

Step-by-step explanation:

You need to remember the Negative exponent rule:

$a^{-n}=\frac{1}{a^n}$

Then, having the equation $9x^{-1} - 2 = 25$, you can rewrite it in this form:

$\frac{9}{x} - 2 = 25$

Now add 2 to both sides of the equation:

$\frac{9}{x} - 2+2 = 25+2\\\\\frac{9}{x}=27$

Multiply both sides of the equation by "x":

$(x)(\frac{9}{x})=27(x)\\\\9=27x$

 And finally divide both sides of the equation by 27.

The value of "x" is:

$x=\frac{9}{27}\\\\x=\frac{1}{3}$