A - actuary...........that is the answer
From the box plot, it can be seen that for grade 7 students,
The least value is 72 and the highest value is 91. The lower and the upper quartiles are 78 and 88 respectively while the median is 84.
Thus, interquatile range of <span>the resting pulse rate of grade 7 students is upper quatile - lower quartle = 88 - 78 = 10
</span>Similarly, from the box plot, it can be seen that for grade 8 students,
The
least value is 76 and the highest value is 97. The lower and the upper
quartiles are 85 and 94 respectively while the median is 89.
Thus, interquatile range of the resting pulse rate of grade 8 students is upper quatile - lower quartle = 94 - 85 = 9
The difference of the medians <span>of the resting pulse rate of grade 7 students and grade 8 students is 89 - 84 = 5
Therefore, t</span><span>he difference of the medians is about half of the interquartile range of either data set.</span>
"-y (less than or greater than sign) 136" translates into two separate inequalities:
-y < 136 and -y > 136.
You want to solve for y in each case. To do this, multiply each inequality by "-1" and then immediately change the direction of the inequality sign.
For example: -1(-y < 136) => y > -136.
<span>-0.00925 is the answer </span><span />
The function is f(x) = 86(1.01)^7x; grows approximately at a rate of 1% daily
<h3>How to rewrite the function?</h3>
The function is given as:
f(x) = 86(1.08)^x
There are 7 days in a week.
This means that:
1 day = 1/7 week
So, x days is
x day = x/7 week
Substitute x/7 for x in
f(x) = 86(1.08)^(x/7)
Rewrite as:
f(x) = 86(1.08^1/7)^x
Evaluate
f(x) = 86(1.01)^x
In the above, we have:
r = 1.01 - 1
Evaluate
r = 0.01
Express as percentage
r = 1%
Hence, the function is f(x) = 86(1.01)^7x; grows approximately at a rate of 1% daily
Read more about exponential functions at:
brainly.com/question/11487261
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