Question

A line passes through the point (-8, 7) and has a slope of negative 3/4Write an equation in slope-intercept form for this line.

Answer 1

Answer:

$y=-\frac{3}{4}x+1$

Step-by-step explanation:

We do not have enough information for slope intercept form. But we can use the point-slope formula to find the information. The formula is $y -y_{1} =m(x -x_{1})$ where we substitute a point (x,y) for $(x_{1},y_{1})$.  

We have m=-3/4 and (-8, 7). We input m and $x_{1} =-8\\y_{1}=7$.

$y-7=-\frac{3}{4} (x-(-8))\\y-7=-\frac{3}{4} (x+8)$

We now simplify the parenthesis and solve for y.

$y-7=-\frac{3}{4} (x+8)\\y-7=-\frac{3}{4}x+-\frac{3}{4} (8)$

We convert 8 into a fraction with 1 as the denoinator.

$y-7=-\frac{3}{4}x+-\frac{3}{4} (\frac{8}{1} )\\y-7=-\frac{3}{4}x+-\frac{24}{4}\\y-7=-\frac{3}{4}x+-6$

We add 7 to both sides to isolate y,

$y-7+7=-\frac{3}{4}x+-6+7\\y=-\frac{3}{4}x+1$

This is slope intercept form. The line as slope -3/4 and y-intercept (0,1) or b=1.