Given :
Walk in forward direction is 30 m .
Walk in backward direction is 25 m .
To Find :
The distance and displacement .
Solution :
We know , distance is total distance covered and displacement is distance between final and initial position .
So , distance travelled is :
D = 30 + 25 m = 55 m .
Now , we first move 30 m in forward direction and then 25 m in backward direction .
So , displacement is :
D = 30 - 25 m = 5 m .
Therefore , distance and displacement covered is 55 m and 5 m respectively .
Hence , this is the required solution .
Answer:
25 seconds
Explanation:
Assuming the woman is accelerating at a constant rate of 
from the initial velocity, u=4.20 m/s, to the final velocity, v=5.00 m/s.
Let she takes t seconds to cover the distance, s=115 m.
As acceleration, 
Now, from the equation of motion
[ from equation (i)]
seconds.
Hence, she takes 25 seconds to walk the distance.
Divide 24 by 12.
24/t = 12
24/12 = t
24/12 = 2
t = 2
Answer:
in co2 there is one atom of carbon
Explanation:
