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2 years ago

What is the acceleration of a 32-kg object if a 6.75-N force is applied to it?

Physics

1 answer:

professor190 [17]2 years ago

5 0

F=MA
*newton 2nd law*
F=6.75N
M=32kg

A= F/M
A=6.75/32
equal
a.0.21m/s2

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Answer:

man will move in opposite direction with speed

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2 years ago

Two teams of nine members each engage in a tug of war. Each of the first team’s members has an average mass of 68 kg and exerts

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F₁ - T = - M₁*a ⇒ T = F₁ + M₁*a

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The complete question is presented in the attached image to this solution.

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Hope this Helps!!!

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