What is the acceleration of a 32-kg object if a 6.75-N force is applied to it?

Physics

1 answer:

professor190 [17]2 years ago

5 0

F=MA
*newton 2nd law*
F=6.75N
M=32kg

A= F/M
A=6.75/32
equal
a.0.21m/s2

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