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bekas [8.4K]
3 years ago
9

What is the acceleration of a 32-kg object if a 6.75-N force is applied to it?

Physics
1 answer:
professor190 [17]3 years ago
5 0
F=MA
*newton 2nd law*
F=6.75N
M=32kg

A= F/M
A=6.75/32
equal
a.0.21m/s2
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