what are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotensue is 15 units long?
1 answer:
Refer to the diagram shown below.
Given:
m∠A = 19°
c = 15
By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835
cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828
Answer:
The lengths are 4.88, 14.18, and 15.00 (nearest hundredth)
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Answer:
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not sure if this is right, but hope it helps
