Perpendicular line always have slopes that are negative reciprocals of one another. Mathematically,
m1*m2=-1
So to be perpendicular to the line given, let's rearrange it to the point slope form of a line...
3y=6x ?3 (not sure what you wanted to type there)
anyway isolating y by dividing both side by three will leave 2x where 2 is the slope.
So for the other line to be perpendicular, m*2=-1, m=-1/2, now we have:
y=-x/2 +b, we can now you the point given to solve for b
4=-2/2 +b
4=-1+b
b=5 so
y=-x/2 +5 or more neatly
y=(10-x)/2
Answer:
B
Step-by-step explanation:
x is the value of x which you input into the function and f(x) is the actual function and therefore the output. so when x=3, f(x)= -2. f(3)=-2
A and E, they are basically at the same point around
The span of 3 vectors can have dimension at most 3, so 9 is certainly not correct.
Check whether the 3 vectors are linearly independent. If they are not, then there is some choice of scalars
(not all zero) such that

which leads to the system of linear equations,

From the third equation, we have
, and substituting this into the second equation gives

and in turn,
. Substituting these into the first equation gives

which tells us that any value of
will work. If
, then
and
. Therefore the 3 vectors are not linearly independent, so their span cannot have dimension 3.
Repeating the calculations above while taking only 2 of the given vectors at a time, we see that they are pairwise linearly independent, so the span of each pair has dimension 2. This means the span of all 3 vectors taken at once must be 2.