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Serjik [45]
4 years ago
13

Differentiating Exponential functions In Exercise,find the derivative of the function. See Example 2 and 3.

Mathematics
1 answer:
kow [346]4 years ago
6 0

Answer:

f'(x)=3ae^{ax}=a f(x), where a be a constant.

Step-by-step explanation:

Note: The given functions is a constant function because variable term is missing.

Consider the given function is

f(x)=3e^{ax}

where a be a constant.

We need to find the derivative of the function.

Differentiate with respect to x.

f'(x)=\dfrac{d}{dx}(3e^{ax})

f'(x)=3\dfrac{d}{dx}(e^{ax})

f'(x)=3e^{ax}\dfrac{d}{dx}(ax)            [\because \dfrac{d}{dx}(e^x)=e^x]

f'(x)=3ae^{ax}

f'(x)=a(3e^{ax})

f'(x)=a f(x)

Therefore, the derivative of the function is f'(x)=3ae^{ax}=a f(x).

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8 0
3 years ago
Find the probability of exactly 3 successes in 6 trials of a binomial experiment in which the probability of success if 50%. rou
stiv31 [10]

Answer:

<u> The probability of exactly 3 successes in 6 trials of a binomial experiment in which the probability of success if 50%, is:</u>

<u>31.3% (Rounding to the nearest tenth)</u>

Step-by-step explanation:

With the information provided, P = 0.5, n = 6 and k = 3, we can build the binomial distribution table, this way:

Binomial distribution (n=6, p=0.5)

 f(x) F(x)

x Pr[X = x] Pr[X ≤ x]

0 0.0156 0.0156

1 0.0938 0.1094  

2 0.2344 0.3438

3 0.3125 0.6563  

4 0.2344 0.8906  

5 0.0938 0.9844  

6 0.0156 1.0000

Under the first column we have the probabilities of success of every value from 0 to 6, and under the second column we have the values for answering the question at least how much probability we have of any number of successes. Our question is exactly 3 successes in 6 trials and we see that value under the first column: 0.3125.

Therefore, the probability of exactly 3 successes in 6 trials of a binomial experiment in which the probability of success if 50%, is:

<u>31.3% (Rounding to the nearest tenth)</u>

Let's recall that the formula for calculating the probability of exact successes is:

P(k out of n) =   (n!/k!(n-k)!) * (p∧k*(1-p)∧(n-k))

in our case p=0.5, n=6, k=3

(n!/k!(n-k)!) = 20 and (p∧k*(1-p)∧(n-k)) = 0.015625

20 * 0.015625 = 0.3125

5 0
3 years ago
Estimate by first rounding each number to the nearest integer.
posledela
4 \frac{1}{9} + 2\frac{ 2}{13} =4 \frac{13}{117} + 2\frac{ 18}{117} =6\frac{31}{117}\approx 6\\ \\Answer: \ \ C.\ \ 6


5 0
3 years ago
5/4 + 4(1/4x1/4)<br><br> Solve
vfiekz [6]
So for this we're going to use this rule: a/b x c/d = ac/bd

simplify 1 x 1 to 1

simplify 4 x 4 to 16

4 x 1/16 to 4/16

simplify 4/16 to 1/4

simplify to 6/4

Lastly simplify

Answer: 3/2

*In decimal form it would be 1.5
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3 years ago
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Vladimir79 [104]

Answer:

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Step-by-step explanation:

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3 years ago
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