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lukranit [14]
3 years ago
7

What value of r makes this equation true? justify your solution. 0.4r - 7 = -.3r +2.8

Mathematics
2 answers:
Georgia [21]3 years ago
6 0

Answer:

all work is pictured and shown

fiasKO [112]3 years ago
3 0

The answer is 14

0.4r-7=-.3r+2.8

Add 7 to both sides. -7+7=0 so it cancels on the left. 2.8+7=9.8.

0.4r=-.3r+9.8.

Add .3r to both sides. -.3r+3r=0 so it cancels on the right. 0.4r+.3r=0.7r.

0.7r=9.8

Divide 0.7 to both sides. 9.8 divided by 0.7 = 14

So r=14

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Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.
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Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}

So, it becomes,

\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ

Hence, the value of cos theta is -0.352.

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