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lukranit [14]
4 years ago
7

What value of r makes this equation true? justify your solution. 0.4r - 7 = -.3r +2.8

Mathematics
2 answers:
Georgia [21]4 years ago
6 0

Answer:

all work is pictured and shown

fiasKO [112]4 years ago
3 0

The answer is 14

0.4r-7=-.3r+2.8

Add 7 to both sides. -7+7=0 so it cancels on the left. 2.8+7=9.8.

0.4r=-.3r+9.8.

Add .3r to both sides. -.3r+3r=0 so it cancels on the right. 0.4r+.3r=0.7r.

0.7r=9.8

Divide 0.7 to both sides. 9.8 divided by 0.7 = 14

So r=14

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The values are a = 7, b = -9, c = -18.

<u>Step-by-step explanation:</u>

The given quadratic equation is 7x^{2} - 9x = 18

The general form of the quadratic equation is ax^{2} + bx + c = 0

where,

  • a is the coefficient of x².
  • b is the coefficient of x.
  • c is the constant term.

Now, you have to modify the given quadratic equation similar to the general form of quadratic equation.

So, bring the constant term 18 to the left side of the equation for equating it to zero.

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⇒ a = 7

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Therefore, the values of a, b, and c are 7, -9 and -18.

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