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lukranit [14]
3 years ago
7

What value of r makes this equation true? justify your solution. 0.4r - 7 = -.3r +2.8

Mathematics
2 answers:
Georgia [21]3 years ago
6 0

Answer:

all work is pictured and shown

fiasKO [112]3 years ago
3 0

The answer is 14

0.4r-7=-.3r+2.8

Add 7 to both sides. -7+7=0 so it cancels on the left. 2.8+7=9.8.

0.4r=-.3r+9.8.

Add .3r to both sides. -.3r+3r=0 so it cancels on the right. 0.4r+.3r=0.7r.

0.7r=9.8

Divide 0.7 to both sides. 9.8 divided by 0.7 = 14

So r=14

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2/5 is the answer because if you add, multiply them together you will get 2/5=40/100%

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Mark As Brainllest

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x%5E2%2B5x%2B3%3D0" id="TexFormula1" title="2x^2+5x+3=0" alt="2x^2+5x+3=0" align="absmiddle"
melamori03 [73]

Answer:

x=-\frac{3}{2},-1

Step-by-step explanation:

2x^2+5x+3=0

Split the second term (5x) into two terms. Multiply the coefficient of the first term (2) by the constant term (3):

2*3=6

Find which two numbers add up to 5 and multiply into 6:

3+2=5\\3*2=6\\3,2

Split 5x as the sum of 3x and 2x:

2x^2+3x+2x+3

Now factor out a common term for the first 2 terms:

2x^2+3x\\x(2x+3)

And do the same for the last 2 terms:

2x+3\\1(2x+3)

Re-insert:

x(2x+3)+1(2x+3)=0

Factor out the common term 2x+3 and insert the values in front of the parentheses (x and 1):

(2x+3)(x+1)=0

Separate the parentheses and equal them to 0. Solve for x:

2x+3=0\\2x+3-3=0-3\\2x=-3\\\\\frac{2x}{2}=\frac{-3}{2}\\\\  x=-\frac{3}{2}

and

x+1=0\\x+1-1=0-1\\x=-1

5 0
3 years ago
15=29-x<br> x=??????????????
zhuklara [117]

15 = 29 - x

15 + x = 29

x = 29 - 15

x = 14

6 0
2 years ago
Just wondering if this is the correct answer...
vaieri [72.5K]
Yes, that should be correct, I am not to sure so don't take my answer as a full yes, but I think that looks correct.
8 0
3 years ago
Read 2 more answers
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