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2 years ago

A botanist transplanted a plant that

Mathematics

1 answer:

KengaRu [80]2 years ago

3 0

Linear equation of plant height is h = (1/2)w + 3

Given:

Height of experimental plant = 3cm

Average growth = 0.5 cm per week

Find:

Linear equation of plant height

Computation:

Given;

h = Plant height

w = number of weeks

So,

Plant height = Height of experimental plant + (Average growth)(number of weeks)

h = 3 + (0.5)(w)

h = (1/2)w + 3

Option "J" is the correct answer to the following question.

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So $n = 6, s = \frac{106}{\sqrt{6}} = 43.27$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 523}{43.27}$

$Z = -2.61$

$Z = -2.61$ has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0

4 years ago

A calculator may be used for this question. The energy saving from recycling one glass bottle will power the oven Adam uses to c

evablogger [386]

The one above is right.

5 0

3 years ago

I need all help possible.

Leviafan [203]

So there are 52 horses
12 of them are white
how many are black?
52 - 12 = 40
there are 40 black horses
12 white horses to 40 black horses
12:40
12/40

Hope this helps :)

5 0

3 years ago

For a function p(x)= x^2-9, what is the inverse function for the domain [0, infinity\

kkurt [141]

An inverse function is a function that reverses another function, so we have a function called:

$p(x)$

Then, the inverse function will be as follows:

$p^{-1}(x)$

Given that $y = p(x)$ , we need to isolate x in terms of y:

$y = x^{2} -9$
∴ $y+9 = x^{2}$

So:

$x=+\sqrt{y+9}$ and $x=-\sqrt{y+9}$

therefore, exchanging variables x and y:

$y=+\sqrt{x+9}$ and $y=-\sqrt{x+9}$
$p^{-1}(x)=+\sqrt{x+9}$ and $p^{-1}(x)=-\sqrt{x+9}$

Which are the figures shown below.

7 0

4 years ago

7 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Elena-2011 [213]

Answer:

Option a. convergent: A

Step-by-step explanation:

a0=3/2

a1=9/8

a2=27/32

a1/a0=(9/8)/(3/2)=(9/8)*(2/3)→a1/a0=3/4

a2/a1=(27/32)/(9/8)=(27/32)*(8/9)→a2/a1=3/4

r=a1/a0=a2/a1→r=3/4

The abosute value of r= !r! = !3/4! = 3/4 = 0.75<1, the series is convergent

7 0

4 years ago