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nataly862011 [7]
3 years ago
10

A 3-mi cab ride costs $7.30. A 8-mi cab ride costs $15.30. Find a linear equation that models a relationship between cost c and

distance d.
Select one:
a. c = 1.91d + 2.50
b. d = 1.60c + 8.00
c. c = 1.60d + 2.50
d. c = 2.43d + 8.00
Mathematics
1 answer:
ASHA 777 [7]3 years ago
7 0

Since, A 3-mi cab ride costs $7.30 and a 8-mi cab ride costs $15.30.

In the information given above, we can consider these as the coordinate points on the axes.

Let (c, d) be the coordinates , where 'c' represents the total cost and 'd' represents the distance traveled.

Cost is on the 'y' axis and distance is on the 'x' axis.

Now, let the first point on the coordinate axes be (3, 7.30) and the other point is given by (8, 15.30).

For the given points say (x_1,y_1) and (x_2,y_2) , equation of line is given by:

(y-y_1)= m(x-x_1) where m(slope) is given by \frac{y_2-y_1}{x_2-x_1}.

The equation of line for the given points is:

(c-7.30) = (\frac{15.30-7.30}{8-3})(d-3)

(c-7.30) = 1.6(d-3)

c-7.30 = 1.6d-4.8

c-1.6d=2.5

So, c = 1.6d+2.5 is the required linear equation that models a relationship between cost c and distance d.

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2 years ago
Newberg City Cafe recently introduced a new flavor of coffee. They served 23 grande cups and 51 jumbo cups of the new coffee tod
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Answer:

Grand coffee cup = 1469 gm

Jumbo coffee cup = 60 gm

Step-by-step explanation:

Let x be the grande coffee cup and y be the jumbo coffee cup.

Solution:

From the first statement. They served 23 grande cups and 51 jumbo cups of the new coffee today, which equal a total of 36,846 grams.

So, the equation is.

23x+51y = 36846 ---------(1)

From the second statement. They served 58 grande cups and 68 jumbo cups of the new coffee tomorrow, which equal a total of 59460 grams.

58x+68y=59460 ----------(2)

Solve the equation 1 for x.

23x = 36846-51y

x=\frac{36846}{23}-\frac{51}{23}y

x=1602-\frac{51}{23}y ---------(3)

Substitute x=1602-\frac{51}{23}y in equation 2.

58(1602-\frac{51}{23}y)+68y=59460

92916-\frac{51\times 58}{23}y+68y=59460

-\frac{2958}{23}y+68y=59460-92916

\frac{-2958+1564}{23}y=-33456  

\frac{-1394}{23}y=-33456

Using cross multiplication.

y=\frac{-23\times 33456}{-1394}

y = 55.99

y ≅ 60 gram

Substitute y = 60 in equation 3.

x=1602-\frac{51}{23}\times 60

x=1602-\frac{3060}{23}

x=1602-133.04

x = 1469 grams

Therefore, grand coffee cup = 1469 gm and jumbo coffee cup = 60 gm

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