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3 years ago

Which equation can be used to solve for x in the following diagram?

Mathematics

2 answers:

charle [14.2K]3 years ago

5 0

Answer:

D. 4x + 5x = 180

Step-by-step explanation:

The two angles form a straight line and a straight line equals 180°. So, the sum of the two angles has to equal 180°.

4x + 5x = 180

9x = 180

x = 20°

Hope that helps.

Kamila [148]3 years ago

3 0

Answer:

D. 4x+5x=180

Step-by-step explanation:

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What is the solution to the equation? 7x + 6 = -22

trapecia [35]

C.) x = -4 is the correct answer

Step-by-step explanation:

In order to solve the equation we have to isolate x on one side of equation

Given

7x + 6 = -22

Subtracting 6 from both sides

$7x+6-6=-22-6\\7x=-28$

Dividing both sides by 7

$\frac{7x}{7}=\frac{-28}{7}\\x=-4$

Hence,

C.) x = -4 is the correct answer

Keywords: Linear equation

Learn more about linear equation at:

#LearnwithBrainly

7 0

3 years ago

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Juliette [100K]

I think the answer would be 1.8

8 0

3 years ago

Vector u has its initial point at (21,12) and its terminal point at (19,-8). Vector v has a direction opposite that of u, whose

agasfer [191]

Step-by-step explanation:

517÷4685568π√7%+66×74367

7 0

3 years ago

Simplify the sum.<br> (4u3 + 4u2 + 2) + (6u3 – 2u + 8)

Elan Coil [88]

Answer:

$10u^{3}+4u^{2}-2u+10$ or $2(5u^{3}+2u^{2}-u+5)$

Step-by-step explanation:

we have

$(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)$

step 1

Group terms that contain the same variable

$(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)$

step 2

Combine like terms

$(10u^{3})+(4u^{2})+(-2u)+(10)$

step 3

Eliminate parenthesis

$10u^{3}+4u^{2}-2u+10$

step 4

Factor the number $2$

$2(5u^{3}+2u^{2}-u+5)$

8 0

3 years ago

Read 2 more answers

What is a cubic polynomial function with zeros 3,3 and -3? show your work.

Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is $\mathbf{x^3-3x^2-9x+27=0}$

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

$(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0$

So, cubic polynomial function with zeros 3,3 and -3 is $\mathbf{x^3-3x^2-9x+27=0}$

4 0

2 years ago