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Arlecino [84]
3 years ago
8

A company sells apples in packages of 444. The masses of the individual apples are normally distributed with a mean of 175\,\tex

t{g}175g175, start text, g, end text and a standard deviation of 15\,\text{g}15g15, start text, g, end text. Assume that the weights of apples are independent from each other.
Mathematics
1 answer:
erastova [34]3 years ago
5 0

Answer: let the probability of  weights less than 160 be the required value, then, using z-score formula

z-score =( x - ∪) ÷ Ф where, x is 160, ∪ is population mean = 175,

Ф is the population standard deviation = 15

  z-score = (160 - 175) ÷ 15 = -1

p(z< -1) = 0.159

Step-by-step explanation:

the question is not complete. Assuming that the missing figure is 160 representing the required weights ess than the normal weights of 175.

step 1. obtain the z-score value by using the formula

          z =( x - ∪) ÷ Ф

step 2. obtain the probability of weights less than 160 from normal distribution table. since z-score value is -1,the probability is obtained as 0.159 that is 15.9%

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Let X the random variable of interest and we know that the confidence interval for the population mean \mu is given by this formula:

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