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3 years ago

The domain !!!!!!!!!!

Mathematics

1 answer:

horsena [70]3 years ago

4 0

The function is undefined where the denominator is zero. The value x=2 must be excluded from the domain.

The 2nd selection, "all real numbers except 2", is appropriate.

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Please heeelp !! <br> Missing triangles !!

Airida [17]

Answer: ABC seem to be equilateral

so A=B=C=60

D=42

E=35

F=35

G=55

H=45

I=45

j=15

k=15

L=75

M=180

N=11

O=35

P=11

Q=55

R=55

S=32

T=32

U=69

Step-by-step explanation:

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3 years ago

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How is a relationship determined when looking at a scatterplot?

snow_tiger [21]

Answer:

The relationship between two variables is called their correlation The relationship between two variables is called their correlation

Step-by-step explanation:

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3 years ago

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Find the point, M, that divides segment AB into a ratio of 5:2 if A is at (1, 2) and B is at (8, 16).

d1i1m1o1n [39]

Since M divides segment AB into a ratio of 5:2, we can say that M is 5/(5+2) of the length of AB. Therefore 5/7 × AB.
distance of AB = d
5/7×(x2 - x1) for the x and 5/7×(y2 - y1) for the y
5/7×(8 - 1) = 5/7 (7) = 5 for the x
and 5/7×(16 - 2) = 5/7 (14) = 10 for the y
But remember the line AB starts at A (1, 2),
so add 1 to the x: 5+1 = 6
and add 2 to the y: 10+2 = 12
Therefore the point M lies exactly at...
A) (6, 12)

4 0

3 years ago

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago

Find a current example of a linear optimization model used in your industry. Describe the industry's needs, including any unique

marishachu [46]

Answer:

Follows are the explanation to the given question:

Step-by-step explanation:

Its determination of inventory amounts for various products. Its demand is an excellent illustration of a dynamic optimization model used in my businesses. Throughout this case, its store has restrictions within this room are limited. There are only 100 bottles of beverages to be sold, for instance, so there is a market restriction that no one can sell upwards of 50 plastic cups, 30 power beverages, and 40 nutritional cokes. Throughout this situation, these goods, even the maximum quantity supplied is 30, 18, and 28. The profit for each unit is $1, $1.4, and $0.8, etc. With each form of soft drink to also be calculated, a linear extra value is thus necessary.

5 0

3 years ago