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igor_vitrenko [27]
3 years ago
7

Pls help and pls provide workings ​

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0

(x-h)²+(y-k)²=r²

(3-h)²+(3-0)²=5²

h²-6h+9+9=25

h²-6h-7=0 —> (h-7)(h+1)=0

h=7 , h=-1

h=7 —> (x-h)²+y²=r² —> (x-7)²+y²=25 —>

x²-14x+49+y²=25 —> x²+y²-14x+24=0

h=–1 —> (x-h)²+y²=r² —> (x+1)²+y²=25 —>

x²+2x+1+y²=25 —> x²+y²+2x–24=0

I hope it helped you ^_^

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then, by SSS postulates we have;

\triangle RST \cong \triangle TUR    


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