The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J
The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.
However, since we are required to determine heat released when the helium gas condenses.
The heat of condensation per gram is; -21 J/g.
Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.
Approximately, -250J.
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I don't know you have to use a measuring tool to figure it out ruler helps sorry try a ruler of a angle scale
When you solve proportions, you have to cross multiply.
9 x
--- = --- Multiply each numerator by the opposite denominator.
11 22
(9)(22) = 11x Then, multiply.
198 = 11x Then, divide.
18 = x
On the unit circle the hypotenuse is always one so we can say:
sinα=y/1 and cosα=x/1 so
The point corresponding the the angle 600° is:
(cos600, sin600) which is approximately
(-1/2, -√(3/4)
Answer:
$600
Step-by-step explanation:
subtract 45 from 75, you get 30. multiply 30 by 20, and there is your answer.