The first equation is ![y-2x+1=0](https://tex.z-dn.net/?f=%20y-2x%2B1%3D0%20)
(Equation 1)
The second equation is
(Equation 2)
Putting the value of x from equation 1 in equation 2.
we get,
![4x^{2}+3(2x-1)^{2}-2x(2x-1)=7](https://tex.z-dn.net/?f=%204x%5E%7B2%7D%2B3%282x-1%29%5E%7B2%7D-2x%282x-1%29%3D7%20)
![4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7](https://tex.z-dn.net/?f=%204x%5E%7B2%7D%2B3%284x%5E%7B2%7D%2B1-4x%29-4x%5E%7B2%7D%2B2x%3D7%20)
by simplifying the given equation,
![12x^{2}-10x-4=0](https://tex.z-dn.net/?f=%2012x%5E%7B2%7D-10x-4%3D0%20)
![6x^{2}-5x-2=0](https://tex.z-dn.net/?f=%206x%5E%7B2%7D-5x-2%3D0%20)
Using discriminant formula,
![D=b^{2}-4ac](https://tex.z-dn.net/?f=%20D%3Db%5E%7B2%7D-4ac%20)
![D=25-4 \times 6 \times -2 = 73](https://tex.z-dn.net/?f=%20D%3D25-4%20%5Ctimes%206%20%5Ctimes%20-2%20%3D%2073%20)
Now the formula for solution 'x' of quadratic equation is given by:
![x=\frac{-b+\sqrt{D}}{2a} and x=\frac{-b-\sqrt{D}}{2a}](https://tex.z-dn.net/?f=%20x%3D%5Cfrac%7B-b%2B%5Csqrt%7BD%7D%7D%7B2a%7D%20%20and%20%20x%3D%5Cfrac%7B-b-%5Csqrt%7BD%7D%7D%7B2a%7D%20)
![x=\frac{5+\sqrt{73}}{12} and x=\frac{5-\sqrt{73}}{12}](https://tex.z-dn.net/?f=%20x%3D%5Cfrac%7B5%2B%5Csqrt%7B73%7D%7D%7B12%7D%20%20and%20x%3D%5Cfrac%7B5-%5Csqrt%7B73%7D%7D%7B12%7D%20)
Hence, these are the required solutions.
Answer:
C
Step-by-step explanation:
The area of the wall hanging shown in blue is the area of the square 8 by 8 minus the area of the cutout. Notice the cutout is a triangle? To find the total area, subtract the area of the triangle from the square.
The square has the sides 8 by 8 and its area is found as A = 8*8 = 64.
The triangle measures 4 inches by 4 inches. The area is found as A = 1/2*4*4 = 8.
Subtract the two areas.
64 - 8 = 56
For example if we have 7/10 we have one 0 in the denominator so we move the decimal spot 1 to the left
So:
7.0 becomes 0.70 or .7
To make a decimal into a fraction:
0.32
Just add two zeros to the right and that means 2 0's will be added in the denominator
so:
0.32
32.0/100 or 32/100
Hope that helps :)
y = 3/2x is the answer for this problem.