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wel
3 years ago
8

7 +(3 x ( 3 + 5)?) + 5

Mathematics
1 answer:
-Dominant- [34]3 years ago
7 0

Answer:

36

Step-by-step explanation:

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Find the range of f(x) = -x2 + 1 for the domain {-2, 0, 2}
wariber [46]
Range is just input the domain

so find f(-2), f(0) and f(2)

f(-2)=-(-2)²+1=-4+1=-3
f(0)=-(0)²+1=0+1=1
f(2)=-(2)²+1=-4+1=-3

range={-3,1}
6 0
3 years ago
Need Help with this..
Goryan [66]

Answer:

119 4/7

Step-by-step explanation:

Add up all the sides

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1 year ago
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Vector u has its initial point at (21,12) and its terminal point at (19,-8). Vector v has a direction opposite that of u, whose
agasfer [191]

Step-by-step explanation:

517÷4685568π√7%+66×74367

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3 years ago
Find the circumference of the circle. Round your answer to the nearest hundredth. Use 3.14 or pi circle is 3 ft in radius
densk [106]

Answer:

18.84 feet

Step-by-step explanation:

The circumference of a circle can be found using:

c=π*d

The radius is given, but we have to find diameter. The diameter is twice the radius, or

d=2r

The radius is 3 feet. Substitute 3 in for r.

d=2*3

d=6

The diameter is 6 feet.

Now we have the diameter. We can substitute 6 in for d in the circumference formula. We can also substitute 3.14 in for pi.

c=π*d

c=3.14*6

c=18.84

The circumference is <u>18.84 feet</u>

8 0
3 years ago
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In ∆MNP, m∠N = 90º, NH – altitude, m∠P = 21º, PM = 4 cm. Find MH.
Sveta_85 [38]

Answer:

0.51 cm

Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

\sin \angle P=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{MN}{MP}\\ \\MN=MP\sin \angle P\\ \\MN=4\sin 21^{\circ}\approx 1.43\ cm

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

\cos \angle M=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{MH}{MN}\\ \\MH=MN\cos \angle M

In the right triangle, two acute angles are always complementary, so

m\angle M=90^{\circ}-m\angle P=90^{\circ}-21^{\circ}=69^{\circ}

Thus,

MH=1.43\cos 69^{\circ}\approx 0.51\ cm

7 0
3 years ago
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