Answer:
1 ≥ t ≤ 3
Step-by-step explanation:
Given
h(t) = -16t² + 64t + 4
Required
Determine the interval which the bar is at a height greater than or equal to 52ft
This implies that
h(t) ≥ 52
Substitute -16t² + 64t + 4 for h(t)
-16t² + 64t + 4 ≥ 52
Collect like terms
-16t² + 64t + 4 - 52 ≥ 0
-16t² + 64t - 48 ≥ 0
Divide through by 16
-t² + 4t - 3 ≥ 0
Multiply through by -1
t² - 4t + 3 ≤ 0
t² - 3t - t + 3 ≤ 0
t(t - 3) -1(t - 3) ≤ 0
(t - 1)(t - 3) ≤ 0
t - 1 ≤ 0 or t - 3 ≤ 0
t ≤ 1 or t ≤ 3
Rewrite as:
1 ≥ t or t ≤ 3
Combine inequality
1 ≥ t ≤ 3
<span>4*((‑(8*x))+5)-(‑(33*x))-26
sorry if this is to hard to understand
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Answer:
√841
Step-by-step explanation:
You would use pythagorean theorem to solve this problem:
a² + b² = c²
a = 20 b = 21
20² + 21² = 400 + 441 = 841
√841
Let x = the number of penguins we are finding
x ÷ 100 × 30 = 15
x = 15 ÷ 30 × 100
x = 50
hope this helps and have a great day :)
Answer:
92
Step-by-step explanation:
