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olga_2 [115]
3 years ago
11

Solve the equation by using the combination method 3x-2y=12 -3x+8y=-6

Mathematics
1 answer:
defon3 years ago
7 0

Combine the 2 equations:


3x-2y=12

-3x+8y=-6

---------------

6y = 6, which tells us that y=1.


Now subst. 1 for y in the 2nd equation: -3x +8(1) = -6.

Then 14=3x, and x = 14/3.


The solution is (14/3,1).


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How many times larger is 3.19 x 10^8 than 8.23 x 10^5? SHOW YOUR WORK!!!
svet-max [94.6K]

In order to find the number times something is larger than something, you have to use division where you divide the larger number by the smaller number.

So:

\frac{3.19*10^8}{8.23*10^5} =387.6063183

I'm not sure how much you want to round to,  but the answer is 387.6063183 times.

You can make sure by multiplying the smaller number by 387.6063183 and you should get the larger number:

8.25*10^5*387.6063183=3.19*10^8

8 0
4 years ago
How many positive integers are factors of 120 and also factors of 40?
olganol [36]

Answer:

8

Step-by-step explanation:

The factors of 120 are:

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 30, 40, 60, 120

The factors of 40 are:

1, 2, 4, 5, 8, 10, 20, 40

All you need to do is find the factors that both numbers share, which are:

1, 2, 4, 5, 8, 10, 20, 40

Count those, and you get 8

6 0
3 years ago
PLESAE HURRY IM BEING TIMED
Brums [2.3K]

Answer:

d

Step-by-step explanation:

3 0
3 years ago
1:2000000 find the land distance 14cm b) 31 cm​
bogdanovich [222]

If the scale is

R.F.= 1/2000000

=1/2x 10000x100

1cm=20000m

The scale of a map is given as= 1/2000000

Two town are 4 cm apart on the map.

the actual distance between two towns

=4x 20000

=80000 m

=80000/1000 Km

=80Km

I hope this help you

6 0
3 years ago
A manufacturer reported a sample mean = 22.0 g and a sample standard deviation = 2.5 g based on a sample of 20 of their products
tester [92]

Answer:

n=(\frac{1.640(2.5)}{2})^2 =4.2 \approx 5

So the answer for this case would be n=5 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=22 represent the sample mean

\mu population mean (variable of interest)

s=2.5 represent the sample standard deviation

n represent the sample size  

ME = 2 represent the margin of error accepted

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (2)

And on this case we have that ME =2 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (3)

We can use as estimator for the population deviation the sample deviation \hat \sigma = s

The critical value for 90% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.05;0;1)", and we got z_{\alpha/2}=1.640, replacing into formula (3) we got:

n=(\frac{1.640(2.5)}{2})^2 =4.2 \approx 5

So the answer for this case would be n=5 rounded up to the nearest integer

6 0
3 years ago
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