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3 years ago

Why do we use average force while solving momentum problems? How is net force related to the momentum of the object?

1 answer:

8 0

So net force is all forces acting on an object and that would make sense with momentum. Say you’re pushing on a box at 100 N but your friend pushes back with 20 N. You wouldn’t plug in 100 N and find the momentum because there is something pushing back on it and it wouldn’t give you the true momentum

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The kinetic energy of an object depends on which of the following?

aleksandr82 [10.1K]

B. the object's speed and mass

Looking at the kinetic energy formula:

1/2mv^2 = Ek

It can be seen that the only two factors that affect the magnitude of the kinetic energy are mass and the object speed. Kinetic energy is also a scalar quantity so the direction is unnecessary.

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3 years ago

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Which variable is the result of the experiment?

lana66690 [7]

Answer:

independent variable is the answer! hope that helps :D

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3 years ago

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A particle of unit mass moves in a potential V(x)= ax^2+b/x^2 . Where a and b are constnts. Calcuate the angular frequency of sm

Sholpan [36]

Answer:

Explanation:

Given

Potential Energy is given by

$U(x)=ax^2+\frac{b}{x^2}$

And Force is given by

$F=-\frac{\mathrm{d} U}{\mathrm{d} x}$

Particle will be at equilibrium when Potential Energy is either minimum or maximum

$F=-\left ( 2ax-\frac{2b}{x^3}\right )$

i.e. $ax=\frac{b}{x^3}$

$x_0=(\frac{b}{a})^{0.25}$

So angular Frequency of small oscillation is given by

$\omega =\sqrt{\frac{U''(x)}{m}}$

for $m=1$

we get $\omega =\sqrt{\frac{U''(x_0)}{1}}$

$U''(x_0)=2a+6a= 8a$

$\omega =\sqrt{8a}$

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3 years ago

A snail moves 40 cm in<br> 20 seconds. How fast<br> did it move?

nasty-shy [4]

Answer:

too fast to be a snail

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2 cm per second

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3 years ago

1. A 1 kg cart moving with a speed of 3 m/s collides with a 2 kg cart at rest. If the carts stick together after the collision,

erica [24]

Answer:

The final speed of the two carts stuck together after the collision is 1 m/s

Explanation:

This is an example of an inelastic collision where two separate carts each with different momentum collide and become a single object.

The conservation of momentum (p) equation is: $p_{1i}+p_{2i}=p_f$ where $p_{1i}$ is the initial momentum of cart 1: $p_{1i}=m_1\,*\,v_{1i}=1\,kg\,*\,3\,\frac{m}{s} = 3 \frac{kg*m}{s}$

Notice that cart 2 is at rest, therefore its velocity is zero, which makes its initial momentum zero: $p_{2i}=m_2\,*\,v_{2i}= 2\,kg \,*0\,\frac{m}{s} =0$

The final momentum ( $p_f$ ) for which we don't know the velocity ( $v_f$ ) is the product of the final mass (addition of the two masses) times the final velocity of this new object (two carts stuck together):

$p_f=(m_1+m_2)* v_f = 3\,kg\,*\,v_f$

Now we re-write the conservation of momentum equation to isolate and obtain the unknown final velocity:

$p_{1i}+p_{2i}=p_f\\3\,\frac{m*kg}{s}+0=3\,kg\,*\,v_f\\3\,\frac{m*kg}{s}=3\,kg\,*\,v_f\\v_f=\frac{3}{3}\, \frac{m}{s} \\v_f=1\,\frac{m}{s}$

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3 years ago