All categories

4 years ago

Given:A=6x-2y B:-4x-8y C:-3x+9y. Commute A+B-C

1 answer:

8 0

A+B-C
A = 6x - 2y
B = -4x - 8y
C = -3x + 9y

(6x - 2y) + (-4x - 8y) - (-3x + 9y)
(6x - 2y) + (-4x - 8y) + (3x - 9y)
2x -10y + (3x - 9y)

5x - 19y

You might be interested in

A roller coaster at the Six Flags Great America amusement park in Gurnee, Illinois, incorporates some clever design technology a

sergeinik [125]

Answer:

a)radius of the arc of the teardrop at the top is 10.58m

b)T = mg

c) the centipetal acceleration at the top is 14.5m/s

Explanation:

Part A

Given that roller coaster is of tear drop shape

So the speed at the top is given as

v = 14.4 m/s

acceleration at the top is given as

a = 2 g

$a = 2(9.8) = 19.6 m/s^2$

now we know the formula of centripetal acceleration as

$a = \frac{v^2}{R}\\$

$19.6 = \frac{14.4^2}{R}\\R = 10.58 m$

Part B

now

the total mass of the car and the ride is M

Let the force exerted by the track be n

By Newton law

$n +Mg =\frac{Mv^2}{r} \\\\n=\frac{Mv^2}{r} -Mg\\\\=M(\frac{v^2}{r}-g )\\\\=M(2g-g)\\\\T=Mg$

Part C

If the radius of the loop is 21.4 m

speed is given by same v = 14.4 m/s

now the acceleration is given as

$a = \frac{v^2}{R}$

$a = \frac{14.4^2}{21.4} \\\\= 9.69 m/s^2$

Now for normal force at the top is given by force equation

$F_n + mg = ma\\F_n = m(a-g)$

The force exerted by the rail is less than zero because acceleration is less than 9.69m/s²

So the normal force would have to point away from the centre, For safe ride this normal force must be positive i.e $a \prec g$

$\frac{v^2}{r} \prec \sqrt{g} \\\\v = \sqrt{rg} \\\\v = \sqrt{21.4 \times 9.8} \\\\v = 14.5m/s$

3 0

3 years ago

HELP ME ASAP PLEASE!!!!!

solmaris [256]

Answer:

f λ = c = 3.00E8 frequency * wavelength = speed of light

λ = c / f = 3.00E8 / 4.0E14 = 7.5E-7 m

Note 1 angstrom = 1.00E-10 m and 1 milli-micron = 1.00E-9 m

So the wavelength would be 7500 angstroms

The visible spectrum is 4000 A - 7000 A or 400 - 700 milli-microns

3 0

3 years ago

A remote-controlled car's wheel accelerates at 22.6 rad/s2 . If the wheel begins with an angular speed of 10.2 rad/s, what is th

Lapatulllka [165]

Answer:

70.9pi rad/s

Explanation:

angle turned through = 16

angular acceleration = 22.6 rad/s2

angular speed = 10.2 rad/s

time = ?

angular acceleration = angular speed/time

time = 10.2/22.6

time = 0.45 seconds

angular speed = angle turned through/time

angular speed = (16 × 2pi)/0.45

= 70.9pi rad/s

3 0

3 years ago

Compared to the amount of heat jupiter receives from the sun, jupiter radiates _____ heat.

uysha [10]

C
http://education.seattlepi.com/planet-gives-off-2-times-much-heat-receives-sun-5420.html

3 0

3 years ago

A car starts from rest and accelerates uniformly over a time of 5.37 seconds for a distance of 101 m. Determine the acceleration

castortr0y [4]

Answer:

8.10m s-2

Explanation:

8 0

4 years ago