3 years ago

A snail moves 40 cm in 20 seconds. How fast did it move?

Physics

1 answer:

nasty-shy [4]3 years ago

5 0

Answer:

too fast to be a snail

......

2 cm per second

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2 years ago

Which of these are point sources of water pollution?

bija089 [108]

Gas stations or sewage treatment facility

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3 years ago

If the ball shown in the figure lands in 0.5 s, about what height was it thrown from?

Ede4ka [16]

Answer: 1.22 m

Explanation:

The equation of motion in this situation is:

$y=y_{o}+V_{oy}t-\frac{g}{2}t^{2}$ (1)

Where:

$y=0$ is the final height of the ball

$y_{o}=h$ is the initial height of the ball

$V_{oy}=V_{o}sin(0\°)=0$ is the vertical component of the initial velocity (assuming the ball was thrown vertically and there is no horizontal velocity)

$t=0.5 s$ is the time at which the ball lands

$g=9.8 m/s^{2}$ is the acceleration due gravity

So, with these conditions the equation is rewritten as:

$h=\frac{g}{2}t^{2}$ (2)

$h=\frac{9.8 m/s^{2}}{2}(0.5 s)^{2}$ (3)

Finally:

$h=1.22 m$

4 0

2 years ago

If spring has a spring constant of 500 N/m and is stretched .50 meters,how much energy is stored in the spring ((show work for f

Free_Kalibri [48]

Answer:

The energy stored is: 62.5 Joules

Explanation:

Given

$k = 500N/m$ --- spring constant

$x = 0.5m$ --- stretch

Required

The amount of energy

This is calculated as:

$U = \frac{1}{2} kx^2$

$U = \frac{1}{2} * 500N/m * (0.5m)^2$

$U = 250N/m * (0.5m)^2$

$U = 62.5\ J$

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2 years ago

A thin wire of length (2 m) and (1 mm2 ) cross-section area is clamped horizontally between two walls, a weight of (10 kg) is hu

allsm [11]

Answer:

Young modulus = 9.8 × 10⁹ N/m²

Explanation:

From the information given:

Stress = F/A

Stress = (10 × 9.8) / 0.001²

Stress = 9.8× 10⁷ N/m²

Strain = increase in length / initial length of wire

Strain = 0.02/ 2

Strain = 0.01

Now;

The Young modulus (Y)= stress/strain

Young modulus = (9.8 × 10⁷ N/m²) / 0.01

Young modulus = 9.8 × 10⁹ N/m²

4 0

2 years ago