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kondaur [170]
2 years ago
5

Evaluate4-2x to the third power when x=3

Mathematics
1 answer:
iren [92.7K]2 years ago
6 0
The answer to your problem would be -8

I got this because if you take 4 - 2x to the third power, it would look like this:
(4 - 2x)^3

All you have to do it plug in 3, solve for the equation in the parentheses, and then take that number to the third power. In this case, you get -2, and if you take that to the third power, you get -8.

Hope this helps!
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Step-by-step explanation:

P = 12.7 + 4 + 2w

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5.01

Step-by-step explanation:

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A ball is drawn at random from a box containing 12 red,18
Lubov Fominskaja [6]

<u>Answer:</u>

<u>For a:</u> The probability of getting a red or blue ball is 0.48

<u>For b:</u> The probability of getting a white, blue or orange ball is 0.81

<u>For c:</u> The probability of getting neither white or orange ball is 0.48

<u>Step-by-step explanation:</u>

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}     .......(1)

We are given:

Number of red balls in a box = 12

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Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

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Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48

  • <u>For b:</u>

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81

  • <u>For c:</u>

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

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