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kondaur [170]
3 years ago
5

Evaluate4-2x to the third power when x=3

Mathematics
1 answer:
iren [92.7K]3 years ago
6 0
The answer to your problem would be -8

I got this because if you take 4 - 2x to the third power, it would look like this:
(4 - 2x)^3

All you have to do it plug in 3, solve for the equation in the parentheses, and then take that number to the third power. In this case, you get -2, and if you take that to the third power, you get -8.

Hope this helps!
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Sydney needs to earn $35 so she can buy her father a birthday present. her mom said she can make $6 per hour cleaning around the
Dmitry_Shevchenko [17]

Answer:

if i can be brainliest that would be great

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

x^2+13x+30 = 0

(x+10)(x+3) = 0

x+10 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

4 0
3 years ago
1) Ten samples of a process measuring the number of returns per 100 receipts were taken for a local retail store.
densk [106]

Answer:

E) .0863

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

For this case we can find the sample proportion for each observation with the following formula:

\hat p = \frac{X}{n}

Where X represent the number of returns and n =100 for each case since the standard value used. Using the last formula we got:

p_1 = \frac{10}{100}=0.1

p_2 = \frac{9}{100}=0.09

p_3 = \frac{11}{100}=0.11

p_4 = \frac{7}{100}=0.07

p_5 = \frac{3}{100}=0.03

p_6 = \frac{12}{100}=0.12

p_7 = \frac{8}{100}=0.08

p_8 = \frac{4}{100}=0.04

p_9 = \frac{6}{100}=0.06

p_{10} = \frac{11}{100}=0.11

And now witht those values we can find the sample mean of proportions with the following formula:

hat p = \frac{\sum_{i=1}^n p_i}{n}= \frac{0.1+0.09+0.11+0.07+0.03+0.12+0.08+0.04+0.06+0.11}{10}=0.081

And we can find the standard error with the following formula:

SE= \sqrt{\frac{\hat p (1-\hat p)}{n}}=\sqrt{\frac{0.081(1-0.081)}{10}}=0.0863

So then the best option on this case is given by:

E) .0863

6 0
3 years ago
AP Calculus redo! I know the answer but can't figure out exactly how to get there. Thank you! I want to work through the steps.
Monica [59]
You're approximating

\displaystyle\int_1^5 x^2\,\mathrm dx

with a Riemann sum, which comes in the form

\displaystyle\int_a^b f(x)\,\mathrm dx=\lim_{n\to\infty}\sum_{i=1}^nf(x_i)\Delta x_i

where x_i are sample points chosen according to some decided-upon rule, and \Delta x_i is the distance between adjacent sample points in the interval.

The simplest way of approximating the definite integral is by partitioning the interval into equally-spaced subintervals, in which case \Delta x=\dfrac{b-a}n, and since [a,b]=[1,5], we have

\Delta x=\dfrac{5-1}n=\dfrac4n

Using the right-endpoint method, we approximate the area under f(x) with rectangles whose heights are determined by their right endpoints. These endpoints are chosen by successively adding the subinterval length to the starting point of the interval of integration.

So if we had n=4 subintervals, we'd split up the interval of integration as

[1,5]=[1,2]\cup[2,3]\cup[3,4]\cup[4,5]

Note that the right endpoints follow a precise pattern of

2=1+\dfrac44
3=1+\dfrac84
4=1+\dfrac{12}4
5=1+\dfrac{16}4

The height of each rectangle is then given by the values above getting squared (since f(x)=x^2). So continuing with the example of n=4, the Riemann sum would be

\displaystyle\sum_{i=1}^4\left(1+\dfrac{4i}4\right)^2\dfrac44

For n=5,

\displaystyle\sum_{i=1}^5\left(1+\dfrac{4i}5\right)^2\dfrac45

and so on, so that the definite integral is given exactly by the infinite sum

\displaystyle\lim_{n\to\infty}\sum_{i=1}^n\left(1+\dfrac{4i}n\right)^2\dfrac4n
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3 years ago
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ser-zykov [4K]

Answer: 118.2

Step-by-step explanation:

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3 years ago
What are the solutions to the following equation? select all that apply. 0= x^2 - x + 5
Dominik [7]

Answer:

I think it is a and f i could be wrong

Step-by-step explanation:

7 0
3 years ago
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