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Gwar [14]
3 years ago
15

Silvio is an air-traffic controller who must calculate the altitude of an incoming plane. He sees the plane at an angle of eleva

tion of 40 as it flies over a signal tower. Silvio knows the signal tower is 3 miles away, so he creates a trigonometric model to calculate the altitude of the plane relative to his own position.
Part A: Did Silvio choose the most appropriate function family for his model?
Part B: Which function family correctly models this situation?

Mathematics
1 answer:
Mrac [35]3 years ago
4 0
Since the problem is not telling us the height of Silvio, we are going to assume it is not relevant for our calculations.
Let h the altitude of the incoming plane. We know for our problem that the distance between Silvio and the tower is 3 miles, Also we know that the angle of elevation to the plane is 40°. With this information we can create a triangle as shown in the figure. We need a function that relates the angle of elevation with its opposite and adjacent sides, that function is tangent.
tan \alpha = \frac{opposite.side}{adjacent.side}
tan(40)= \frac{h}{3}
h=3tan(40)
h=2.5miles

We can conclude that we should use the trig function tangent to model this situation; also, we can conclude that the equation that describes this situation is h=3tan(40).

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Sedaia [141]
Commission=0.06×764=$45.84
7 0
3 years ago
What is 84/5 divided by 4 =
dangina [55]

THe answer is, 21/5

And in decemal form it will be, 4.2

5 0
3 years ago
What is the slope of the line that contains these points? xxx -4−4minus, 4 -3−3minus, 3 -2−2minus, 2 -1−1minus, 1 yyy 222 555 88
Charra [1.4K]

Given:

The table of values is

x        y

-4      2

-3      5

-2       8

-1       11

To find:

The slope of the line that contains these points.

Solution:

From the given table consider any two point.

Let the line passes through the points (-4,2) and (-3,5). So, the equation of the line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-2=\dfrac{5-2}{-3-(-4)}(x-(-4))

y-2=\dfrac{3}{-3+4}(x+4)

y-2=\dfrac{3}{1}(x+4)

Using distributive property, we get

y-2=3x+12

y=3x+12+2

y=3x+14

Therefore, the required equation of line is y=3x+14.

4 0
3 years ago
Answer this question please and thank you
ELEN [110]

Answer:

x = -11

-11-3=-14

-14/7=-2

7 0
3 years ago
The midpoint of line CD is M(-3,-7). If the coordinates of C are (-2, -10), what are the coordinates of D?
Lynna [10]

Answer:

D = (-4, -4)

Step-by-step explanation:

Given;

midpoint of line CD = M(-3, -7)

coordinate of C = (-2, -10)

The coordinate of D is calculated as follows;

C(-2, -10)---------------------M(-3, -7)--------------------D

M = \frac{D_1 + C_1}{2} \ , \ \frac{D_2 + C_2}{2} \\\\(-3, \ -7) = \frac{D_1 + (-2)}{2} , \ \frac{D_2 + (-10)}{2} \\\\(-3, \ -7) = \frac{D_1 \ - \ 2}{2} , \ \frac{D_2 -10}{2} \\\\-3 =  \frac{D_1 \ - \ 2}{2}  \ \ ----(1)\\\\-7 =  \frac{D_2 -10}{2}  \ -----(2)\\\\From \ (1): 2(-3) = D_1\ - \ 2\\\\-6 = D_1 - 2\\\\-6 + 2 = D_1\\\\-4 = D_1\\\\From \ (2) : \ 2(-7) = D_2 - 10\\\\-14 = D_2 - 10\\\\ -14 + 10 = D_2\\\\-4 = D_2\\\\The \ coordinate \ of \ D = (D_1\ , \ D_2)\\\\D = (-4 \ , \ -4)

Therefore, the coordinate of D = (-4, -4)

6 0
3 years ago
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