1/10, 2/10, 3/10, 2/5, 1/2, 3/5, 7/10, 9/10.
Answer:
We know that the equation for the speed is:
Speed = Distance/time.
First, we know that he walks 2 miles in 15 minutes.
distance = 2miles
time = 15 minutes
Then his speed in that interval is:
Speed = (2 mi)/(15 min) = (2/15) miles per minute.
Now, at this same speed, he wants to walk 3 more miles. And we want to find the equation that represents how much time she needs to walk 5 miles (the 2 first miles plus the other 3 miles)
We use again the equation:
Speed = Distance/Time
But we isolate Time, to get:
Time = Distance/Speed
Where:
Distance = 5 miles
Speed = (2/15) miles per min
Time = (5 miles)/((2/15) miles per min) = 37.5 minutes
She needs 37.5 minutes to walk the 5 miles.
Hey there!
In order to answer this question, it's easiest to start with one of the money amounts and work your way to the other ones. Keep in mind that, no matter what, the amount of collective money won't exceed 1.50, meaning you can't have two 1 dollar bills, etc. When I wrote it out, I did it in this order:
1 = 1 dollar
0.5 = Half dollar
0.25 = Quarter
1 + 0.5 = 1.50
1 + 0.25 + 0.25 = 1.50
0.5 + 0.5 + 0.5 = 1.50
0.5 + 0.5 + 0.25 + 0.25 = 1.50
0.5 + (0.25*4) = 1.50
0.25*6 = 1.50
Since no other combinations add up to 1.50, your answer is 6.
Hope this helped you out! :-)
Answer:

General Formulas and Concepts:
<u>Algebra I</u>
Terms/Coefficients
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Quotient Rule]: ![\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B%5Cfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%20%5D%3D%5Cfrac%7Bg%28x%29f%27%28x%29-g%27%28x%29f%28x%29%7D%7Bg%5E2%28x%29%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Derivative Rule [Quotient Rule]:

- Basic Power Rule:

- Exponential Differentiation:

- Simplify:

- Rewrite:

- Factor:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation