Please Help! Will mark Brainliest for correct answer! 12 POINTS!

The green darner is one of the largest dragonflies. It weighs about four hundredths of an ounce. Write four hundredths in standa

Tju [1.3M]

Answer:

Four hundredths

In standard form - $4\times 10^{-2}$

Step-by-step explanation:

Given : The green darner is one of the largest dragonflies.

It weighs about four hundredths of an ounce.

To write : Four hundredths in standard form.

Solution :

Standard form is when we write a larger number in a smaller way.

For example : $20000= 2\times 10^4$

So, according to question

Largest dragonflies weighs about four hundredths of an ounce.

Four hundredths means 0.04

In standard form - $4\times 10^{-2}$

7 0

2 years ago

he mayor of a town has proposed a plan for the construction of an adjoining community. A political study took a sample of 160016

Diano4ka-milaya [45]

Answer:

2.60

Step-by-step explanation:

Given that:

n = 1600

$\hat p = 0.34$

$P_o = 0.31$

The test statistics can be computed as:

$Z = \dfrac{\hat p - P_o}{\sqrt{ \dfrac{P_o\times (1-P_o) } {n} }}$

$Z = \dfrac{0.34-0.31}{\sqrt{ \dfrac{0.31 \times (1-0.31) } {1600} }}$

$Z = \dfrac{0.03}{\sqrt{ \dfrac{0.31 \times (0.69) } {1600} }}$

$Z = \dfrac{0.03}{\sqrt{ \dfrac{0.2139} {1600} }}$

$Z = 2.60$

4 0

3 years ago

Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution

Iteru [2.4K]

Consider the equation:

$\sqrt{x+2}+4 = 8$

Subtracting '4' from both the sides of the equation, we get as

$\sqrt{x+2}+4-4= 8-4$

$\sqrt{x+2}= 4$

Squaring on both the sides of the equation, we get

$(\sqrt{x+2})^2 = (4)^2$

$x+2 = 16$

Subtracting '2' from both the sides of the equation, we get

$x+2-2=16-2$

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

4 0

3 years ago

Read 2 more answers

Please help please !!!

Kobotan [32]

<h3>Answer: 12</h3>

========================================================

Explanation:

You can use the AAS (angle angle side) theorem to prove that triangle ABD is congruent to triangle CBD.

From there, we can then say that AD and DC are the same length

AD = DC

3y+6 = 5y-18

3y-5y = -18-6

-2y = -24

y = (-24)/(-2)

y = 12

6 0

2 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago