$\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}$

The applicable rules of logarithms are ...

log(ab) = log(a) +log(b)

log(a/b) = log(a) -log(b)

log(a^b) = b·log(a)

3 0

3 years ago

a ferry traveled 1/6 of the distance between two ports in 3/7 hour. The ferry travels at a constant rate.how much do the ferry t

Dahasolnce [82]

Answer:

1 hour = 7/18 of the distance between two ports

Step-by-step explanation:

Given that:

In 3/7 hours distance traveled is 1/6

For finding distance in one hour, divide both sides by 7/3 so that 3/7 would be cancelled out:

3/7 * 7/3 hours = 1/6 * 7/3 distance

By simplifying:

1 hour = 7/18 of the distance between two ports

This means that in one hour 7/18 of the distance is covered between two ports.

i hope it will help you!

8 0

3 years ago

Read 2 more answers