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3 years ago

BEST ANSWER GET BRAINLIEST

1 answer:

8 0

1500 / 100 = 15 (This is how much 1% of 1500 is)
15 * 4 = 60 ( This is 4% of 1500)
60 * 6 = 120

He will earn 120 dollars over a 6 year time period, with 4% interest.

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A straw is placed inside a rectangular box that is 2" x 6" x 8". If the straw fits exactly into the box diagonally from the bott

den301095 [7]

Answer: $10.2"$

Step-by-step explanation:

Given

The dimension of the rectangular box is $2"\times 6"\times8"$

If the Straw fits exactly into the box diagonally

So, the length of the longest diagonal of the rectangular box is equal to the length of the straw i.e.

$\Rightarrow l=\sqrt{2^2+6^2+8^2}\\\\\Rightarrow l=\sqrt{4+36+64}\\\\\Rightarrow l=\sqrt{104}\\\Rightarrow l=10.19\approx 10.2"$

4 0

3 years ago

The GCD(a, b) = 6, the LCM(a, b)=180. Find the least possible value of a+b.

Fantom [35]

The factors of 180 are
(1, 180), (2, 90), (3, 60), (4, 45), (5, 36), (6, 30), (9, 20), (10, 18), (12, 15).

The GCD of 6 is the largest positive integer that divides 180.
Therefore the required factors of 180 are a=6 and b=30 or vice versa.
a + b = 6 +30 = 36

Answer: 36

3 0

3 years ago

Solve 3x−5 = 9. (1 point) a x = −3 b x = 2 c x = 7 d x = 8

n200080 [17]

Answer:
d) x = 8

Explanation:
3x - 5 = 9
(3x / 3) - 5 = 9/3
x - 5 = 3
x (- 5 + 5) = 3 + 5
x = 8

7 0

3 years ago

Read 2 more answers

Which distribution is used to test the claim that women have a higher mean resting heart rate than men?

xeze [42]

This question is incomplete, the complete question is;

Assume that two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Which distribution is used to test the claim that women have a higher mean resting heart rate than men?

A.t

B.F

C.Normal

D. Chi-square

Answer:

A) t test

Step-by-step explanation:

A t-test uses sample information to assess how plausible it is for the population means μ1 and μ2 to be equal.

The formula for a t-statistic for two population means (with two independent samples), with unknown population variances shows us how to calculate t-test with mean and standard deviation and it depends on the assumption of having an equal variance or not.

If the variances are assumed to be not equal,

he formula is:

t = (bar X₁ - bar X₂) / √( s₁²/n₁ + s₂²/n₂ )

If the variances are assumed to be equal, the formula is:

t = (bar X₁ - bar X₂) / √ (((n₁ - 1)s₁² + (n₂ - 1)s₂²) / (n₁ + n₂ - 2)) ( 1/n₁ + 1/n₂)

it called t-test for independent samples because the samples are not related to each other, in a way that the outcomes from one sample are unrelated from the other sample.

hence option A is correct. t test

4 0

3 years ago

Problem PageQuestion An automobile manufacturing plant produced 34 vehicles today: 16 were motorcycles, 9 were trucks, and 9 wer

8_murik_8 [283]

Answer:

Probability that the first vehicle selected is a motorcycle and the second vehicle is a van is (24/187) or 0.1283.

Step-by-step explanation:

We are given that an automobile manufacturing plant produced 34 vehicles today: 16 were motorcycles, 9 were trucks, and 9 were vans.

Plant managers are going to select two of these vehicles for a thorough inspection. The first vehicle will be selected at random, and then the second vehicle will be selected at random from the remaining vehicles.

As we know that, Probability of any event = $\frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}$

Now, Probability that the first vehicle selected is a motorcycle is given by;

= $\frac{\text{Number of motorcycles}}{\text{Total number of vehicles}}$

Here, Number of motorcycles = 16

Total number of vehicles = 16 + 9 + 9 = 34

So, Probability that the first vehicle selected is a motorcycle = $\frac{16}{34}$

Similarly, Probability that the second vehicle is a van is given by;

= $\frac{\text{Number of vans}}{\text{Total number of remaining vehicles}}$

Here, Number of vans = 9

And Total number of remaining vehicles after selecting one motorcycle = 34 - 1 = 33

So, Probability that the second vehicle selected is a van = $\frac{9}{33}$

Therefore, the probability that the first vehicle selected is a motorcycle and the second vehicle is a van = $\frac{16}{34}\times \frac{9}{33}$

= $\frac{24}{187}$ = 0.1283

5 0

3 years ago