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Anna007 [38]
3 years ago
5

How to expand this logarithm?

Mathematics
1 answer:
Zarrin [17]3 years ago
5 0
There is a division symbol, division is subtracted. Are you sure you have the problem stated clearly?
<span>ln( \frac{-5m-3}{ \sqrt{-4m-7} } )\\  \\ ln(-5m-3) - ln( (-4m-7)^{1/2} ) \\ \\ Power Rule  \\  \\ ln(-5m-3) -  \frac{1}{2} ln(-4m-7)

</span>
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Find the average rate of change over the given interval <br> f(x) = 2^x , [3,5]
Vlada [557]

Answer:

y=x*2^x (3,5)+y

Step-by-step explanation:

4 0
2 years ago
Question 3
nalin [4]

Answer:

idk

Step-by-step explanation:

i+d+k= idk

6 0
3 years ago
Change the fraction to a decimal with division 1/10
Viktor [21]

Answer: 0.1

Step-by-step explanation: you only need to add zero to the first value,

for example if you have 1/10, you add zero, getting the next equation

10/10 if you add a zero to value you can add a zero to the result getting the following result

10/10=0. in this point both values are divisible

and 10 between 10 is equal to 1

as you finish add zeros you can add a point and after the 1 getting this result

1/10 = 0.1

 

7 0
3 years ago
Read 2 more answers
In parallelogram ABCD, base AD is 15 and side AB is 8. What are the height and area of paralelogram ABCD if mDAB is 20?
Goshia [24]

Step-by-step explanation:

✰ \underline{ \underline{ \large{ \tt{G\: I \: V \: E \: N}}}} :

  • AD = 15 , AB = 8 , \angle DAB

✰ \underline{ \underline{ \large{ \tt{T \: O \: \: F\: I \: N \: D}}}} :

  • Height & Area of the given parallelogram

✰ \underline{ \underline{ \large{ \tt{S \: O \: L \: U \: T\: I\: O \: N}}}} :

In right angled triangle ABE :

  • Hypotenuse ( h ) = 8
  • Perpendicular ( p ) = h [ height ]
  • \theta = 20°

Now , Using trigonometric ratio :

\large{ \tt{Sin \theta \:  = \:  \frac{Perpendicular}{Hypotenuse}  }}

Plug the known values :

⟶ \large{ \tt{ Sin(20)  =  \frac{h}{8} }}

⟶ \large{ \tt{0.34 =  \frac{h}{8}}}

⟶ \large{ \tt{h = 0.34 \times 8}}

⟶ \large{ \tt{h = 2.72}}

Now , We have :

  • Base ( b ) = 15
  • Height ( h ) = 2.72

Finding the area of a parallelogram whose base and height are 15 and 2.72 respectively :

❀ \underline{ \underline{ \text{Area \: of \: parallelogram =  \tt{b   *\:  h}}}}

⟶ \large{ \tt{A = 15  *2.72}}

⟶ \large{ \tt{A = 40.8 \:  {units}^{2} }}

Hence , Our final answer :

\large{ \boxed{ \sf{Height \: ( \: h \: ) = 2.72 \: units}}}

\large{ \boxed{ \sf{Area \: of \: parallelogram \: ( \:A \: ) = \: 40.8 \:  {units}^{2} }}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

# \underbrace{ \tt{Carry \: On \: Learning}} !! ✎

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

3 0
3 years ago
Please Help will award brainliest
EastWind [94]

Answer:7

Step-by-step explanation:

Remember,

PEMDAS

Begin by 3 / 1/3 = 1

1+1=2

9-2 = 7

3 0
3 years ago
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