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Anna007 [38]
3 years ago
5

How to expand this logarithm?

Mathematics
1 answer:
Zarrin [17]3 years ago
5 0
There is a division symbol, division is subtracted. Are you sure you have the problem stated clearly?
<span>ln( \frac{-5m-3}{ \sqrt{-4m-7} } )\\  \\ ln(-5m-3) - ln( (-4m-7)^{1/2} ) \\ \\ Power Rule  \\  \\ ln(-5m-3) -  \frac{1}{2} ln(-4m-7)

</span>
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Need help ASAP i am timed
Nadya [2.5K]
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Just search it up on a math website or sum
8 0
3 years ago
Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and
Irina18 [472]

Answer: tea = 15 rupees  per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997": </em>

2 t + 3 s =39 (a)

Where:

  • t= price of 1 kg of tea
  • s = price of 1 kg of sugar

<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "</em>

2(t1.25)+3(s1.2) = 48.30 (b)

  • <em>Solving for t in (b) </em>

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

  • <em>Replacing the value of t in (b) </em>

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

  • <em>Replacing the value of s in (a) </em>

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
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Answer:

I'm not good with this stuff myself... lol

Step-by-step explanation:

All real numbers. X€R

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Answer:

56

Step-by-step explanation:

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3 years ago
3,497,109.0 plus 6,723.97
Mashutka [201]
3,503,832.97 hope this helps! :)
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