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Mademuasel [1]
3 years ago
9

Simplify the expression 4p - 5(p+6)

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
8 0
<span>4p - 5 • (p + 6)

</span>-p - 30  =   -1 • (p + 30)<span> 
</span>
<span> -p - 30</span>
Virty [35]3 years ago
6 0
-p+-30 is the answer hope this helps. :)
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The costs of different weights of onions sold at a grocery store are shown in the table below. What are the independent and depe
Furkat [3]

Answer:

Independant = onions wight. Dependent = cost.

Step-by-step explanation: The Cost depends on how much the onions weight.

3 0
2 years ago
Suppose your friends parents invest $15,000 in an account paying 6% compounded annually. What will be the balance after 9 years
JulijaS [17]
A = 15000(1.04)6 .........You can put this into your calculator such that it becomes
A = $18,979.79
6 0
2 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
on a certain planet, objects weight about 7/12 of what they weigh on earth. an object weights 13 5/12 pounds on the planet. solv
Cloud [144]
Although the concept here is physics, the solution is technically just algebra. You have two situations that are related to each other which can be expressed in equation form. Actually, the equation is already given which is <span>7/12 w= 13 5/12. So, basically, all you have to do is solve for w.

Let's simplify 13 5/12 first into an improper fraction.You do this by multiplying the denominator with the whole number and adding to it the numerator. This will be your new numerator, The denominator would still be 12. So, this is equal to (12*13 + 5)/12 = 161/2. Then,

(7/12) w = 161/12

By cross multiplication,

7*12*w = 161*12
w = 161/7 = 23

Therefore, w = 23 pounds which is the weight of the object on Earth.


</span>
8 0
3 years ago
Complete the Magic Square.
quester [9]

Answer:

+5

Step-by-step explanation:

So you can see the 5 pattern, so you add 9+5= 14 which goes in the middle square and 14+5=18 in the left square

Now between 18 and 11 it is 7 so you subtract 7 which equals 4 then - 5= -1 then -5= -6

5 0
3 years ago
Read 2 more answers
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