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Firlakuza [10]
2 years ago
12

in Yoshi's garden three quarters of the flowers are tulips of the tulips 2/3 of them are yellow what fraction of the flowers in

Yoshi's garden are yellow tulips
Mathematics
1 answer:
PtichkaEL [24]2 years ago
4 0
So 3/4 of flowers are tulips
2/3 of tulips are yellow
what fraction are yellowtulips
2/3 of 3/4 are yellow tulips
'of' means mutily
2/3 times 3/4=(2 times 3)/(3 times 4)=6/12=1/2

answer is 1/2
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snow_tiger [21]

in plain and short, is just their product.

now, let's convert the mixed fractions to "improper" firstly, and then multiply.

\bf \stackrel{mixed}{1\frac{1}{4}}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}} \\\\\\ 8\cdot 8\cdot \cfrac{5}{4}\implies \cfrac{8\cdot 8\cdot 5}{4}\implies \cfrac{320}{4}\implies 80

7 0
3 years ago
Which of the following is a composite number?
Jobisdone [24]
A composite number is number with factors that are made up of not just 1 and itself.

For the first question, the composite number is
b. 49

Relatively prime numbers are numbers which do not have common factors other than 1.

For the second question, the relatively prime numbers are
<span>c. 46 and 87</span>
4 0
3 years ago
What is 7.2 times 10^5 equal to.
FromTheMoon [43]
The answer to this is 720000
4 0
3 years ago
Read 2 more answers
Evaluate 2b² - 3b + 4a² for a= -6 and b=8
eduard

Answer:

Step-by-step explanation:

2b^2 - 3b + 4a^2........a =-6 and b = 8

now we sub

2(8^2) - 3(8) + 4(-6^2)

2(64) - 24 + 4(36)

128 - 24 + 144

272 - 24

248 <==

7 0
3 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
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